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dolphi86 [110]
2 years ago
6

HELP ASAP PLEASE WILL MARK BRAINLIEST!!!!!!

Mathematics
1 answer:
Lesechka [4]2 years ago
4 0

Answer:

10) \frac{m^{12} }{m^{12}} = m^{0} = 1

11) 9n^{0} = 9 · 1 = 9

12) 179^{0} = 1

13) p^{-2} · p^{3} = p

14) \frac{q^{12} }{q^{14} } = q^{-2}

15) \frac{v^{3} }{v^{8} } = v^{-5}

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If we measured the heights of different plants and got 50”, 55”, 48”, 50” and 52”. What
mr Goodwill [35]

Answer:

B

Step-by-step explanation:

50+55+48+50+52=255

255/5=51

Anwser 51

5 0
2 years ago
dario rolled a number cube and flipped a coin. the number cube has 6 sides, each labeled either 1,2,3,4,5, and 6. what is the pr
aleksklad [387]
I can use a chart by numbers them on the chart because I think 4 should be after the 3
5 0
3 years ago
Write the equation of a quadratic function who has the vertex of (4,-7)
timama [110]

Given:

The vertex of a quadratic function is (4,-7).

To find:

The equation of the quadratic function.

Solution:

The vertex form of a quadratic function is:

y=a(x-h)^2+k          ...(i)

Where a is a constant and (h,k) is vertex.

The vertex is at point (4,-7).

Putting h=4 and k=-7 in (i), we get

y=a(x-4)^2+(-7)

y=a(x-4)^2-7

The required equation of the quadratic function is y=a(x-4)^2-7 where, a is a constant.

Putting a=1, we get

y=(1)(x-4)^2-7

y=(x^2-8x+16)-7             [\because (a-b)^2=a^2-2ab+b^2]

y=x^2-8x+9

Therefore, the required quadratic function is y=x^2-8x+9.

6 0
2 years ago
Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t
DerKrebs [107]

Isolate one variable in the system of equations. Use substitution to create a one-variable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.

4 0
3 years ago
Read 2 more answers
2x+2y=10 solve for x
irakobra [83]

Isolate the x. Note the equal sign. What you do to one side you do to the other.


Subtract 2y from both sides


2x + 2y (-2y) = 10 (-2y)


2x = 10 - 2y


Isolate the x, divide 2 from both sides and from all terms.


(2x)/2 = (10 - 2y)/2


x = 5 - y


Place the variable in the front


x = -y + 5


x = -y + 5 is your answer


hope this helps

7 0
2 years ago
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