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EastWind [94]
3 years ago
5

The local grocery store sells a bag of dog food for $22. The store pays $13 for the dog food. Which equation can be used

Mathematics
1 answer:
dezoksy [38]3 years ago
6 0

Answer:

i don't get it which class q is this?

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5/6 b + 5 - 2/3 b -2
Oksana_A [137]

Answer:

1/6 b+3

Step-by-step explanation:

6 0
3 years ago
What’s the value of X ???!!!!
Alexus [3.1K]

Answer:

Step-by-step explanation:

So since triangle jkl and wyz are similar angles j and w must equal each other, angles k and y must equal each other, and angles l and z are equal. So to find x just set 4x-13 equal to 71

4x-13=71

add 13 to both sides to cancel the -13 from the left

4x=84

and divide both sides by 4 to cancel the 4 on the left

x=21

7 0
3 years ago
He simultaneous equations<br>5x + y = 21<br>x - 3y = 9 <br><br>With working out​
Elza [17]

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

5x + y = 21 → (1)

x - 3y = 9 → (2)

Multiply (1) by 3 and add the result to (2) to eliminate y term

15x + 3y = 63 → (3)

Add (2) and (3) term by term

(x + 15x) + )- 3y + 3y) = (9 + 63)

16x = 72 ( divide both sides by 16 )

x = 4.5

Substitute x = 4.5 into (1) for corresponding value of y

22.5 + y = 21 ( subtract 22.5 from both sides )

y = - 1.5

Solution is (4.5, - 1.5 )

8 0
3 years ago
Select either relation (if the set is a relation but not a function), function (if the set is both a relation and a function), o
galina1969 [7]

Answer:  The correct options are

(A) relation

(B) function.

Step-by-step explanation:  We are given to check whether the following set is a relation or a relation and a function or neither :

A = {(1, 2) (2, 2) (3, 2) (4, 2)} .

Let us consider the following two sets :

U = {1, 2, 3, 4}  and  V = {2}.

Then, we see that the Cartesian Product of U and V is given by

U × V = {(1, 2) (2, 2) (3, 2) (4, 2)}.

Since a relation is a subset of Cartesian product, so the given set A is a relation.

Also, we know that a relation is a function if every first element is associated with one second element.

Since the relation A satisfies this condition, so the relation A is a function.

Thus, the given set A is both a relation and a function.

Option (A) and (B) are correct.

6 0
3 years ago
Tulong nmn po plsss​
mylen [45]

Answer:

tohw9

ufpa

Step-by-step explanation:

jfapn

abjllj shllhphkvq gohahogsv 79qy75j

7 0
3 years ago
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