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anyanavicka [17]
3 years ago
6

Calculate the volume, in liters, occupied by 0.775 mol of oxygen gas at STP.

Chemistry
1 answer:
jeka57 [31]3 years ago
6 0

Answer:

17.4 L

Explanation:

Step 1: Given data

  • Moles of oxygen (n): 0.775 mol
  • Pressure of the gas (P): 1 atm (standard pressure)
  • Temperature of the gas (T): 273.15 K (standard temperature)

Step 2: Calculate the volume occupied by 0.775 moles of oxygen at standard temperature and pressure (STP)

At STP, 1 mole of an ideal gas occupies 22.4 L.

0.775 mol × 22.4 L/1 mol = 17.4 L

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When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find
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<h3>Answer:</h3>

Balanced equation: 4Fe + 3O₂ → 2Fe₂O₃

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<h3>Explanation:</h3>

To answer the question;

  • We first write the balanced equation between iron metal and Oxygen
  • The balanced equation is given as;

4Fe + 3O₂ → 2Fe₂O₃

  • We are given 6 moles of Fe₂O₃

We are required to determine the number of moles of oxygen needed to form 6 moles of Fe₂O₃.

  • From the equation, 3 moles of oxygen gas reacts to produce 2 moles of Fe₂O₃
  • This means, the mole ratio of O₂ to Fe₂O₃ is 3 : 2

Therefore; Moles of O₂ = Moles of Fe₂O₃ × 3/2

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