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patriot [66]
3 years ago
14

Which of the following elements possesses an expanded octet?

Chemistry
1 answer:
stepan [7]3 years ago
8 0
I think xe possess expanded octet
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Consider the balanced equation below. 4nh3 3o2 right arrow. 2n2 6h2o what is the mole ratio of nh3 to n2? 2:4 4:2 4:4 7:2
KIM [24]

The required mole ratio of  NH₃ to N₂ in the given chemical reaction is 2:4.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.

Given chemical reaction is:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

From the stoichiometry of the reaction it is clear that:

4 moles of NH₃ = produces 2 moles of N₂

Mole ratio NH₃ to N₂ is 2:4.

Hence required mole ratio is 2:4.

To know more about mole ratio, visit the below link:
brainly.com/question/504601

3 0
3 years ago
Determine the equilibrium pH and speciation (concentration of each species) of the following two solutions. Neglect activity cor
irina [24]

Answer:

HCl solution - H30+ and Cl ions. pH 3

NaCl - Na+ and Cl-. pH 7

Explanation:

a) HCl solution - the hydrogen ion combines with water molecule to form the hydronium molecule which is responsible for acidity. The chloride ion is also found in solution.

pH = -log [H+] = -log(10^-3) = 3

b) NaCl 10-3 g. The solid dissocates in water forming the Na+ and Cl- ions. None of these ions affect pH

5 0
4 years ago
Does anyone know the answer???​
Fofino [41]
Yes the correct answer is 3.14
5 0
3 years ago
Read 2 more answers
A student prepared a stock solution by dissolving 20.0 g of NaOH in enough water to make 150. mL of solution. She then took 15.0
pav-90 [236]

Answer:

0.769\ \text{M}

Explanation:

Mass of stock solution = 20 g

Molar mass of NaOH = 40 g/mol

Volume of stock solution = 0.150 mL

M_2 = Concentration of NaOH for the final solution

V_1 = Amount of stock solution taken = 15 mL

V_2 = Total volume of solution = 65 mL

Molarity is given by

M_1=\dfrac{\text{Mass}}{\text{Molar mass}\times \text{Volume}}\\\Rightarrow M_1=\dfrac{20}{40\times 0.15}\\\Rightarrow M_1=\dfrac{10}{3}

We have the relation

M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{\dfrac{10}{3}\times 15}{65}\\\Rightarrow M_2=0.769\ \text{M}

The concentration of NaOH for the final solution is 0.769\ \text{M}.

5 0
3 years ago
In the gizmo what light intensity in CO2 level do you think will maximize the rate photosynthesis
Phoenix [80]
<span>Carbon dioxide is one of the important factor in photosynthesis. It helps photosynthesis to take place and it will increase its rate provided the Oxygen supply level at night remains constant.It would probably keep increasing up to 100 percent assuming the light was on. The plant probably needs O2 at night. They generally don't make greenhouses more than about 1000 ppm because the improvement isn't worth the cost of pumping in all that extra CO2. The amount of light that the plant absorbs limits the benefit so it won't increase in proportion to the amount of CO2 past a certain point. It wouldn't be much improvement past about 5000 ppm from what I have heard before.</span>
8 0
4 years ago
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