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Usimov [2.4K]
2 years ago
11

Craig solicited donations for his school's jump-rope a-thon. He collected $13.00 in fixed donations and pledges totaling $1.50 f

or each minute, m, he jumps rope at the event. The total amount of money Craig has
raised is represented by the expression: 13 +1.50m.
What is the total amount of money Craig will raise if he jumps rope for 8 minutes?

HELP MEH PLA ASAP
Mathematics
1 answer:
charle [14.2K]2 years ago
8 0

Answer:

25

Step-by-step explanation:

13+1.50m

13+1.50(8)

13+12

25

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A deposit of 4000 at 9.5% for 270 days
Lapatulllka [165]
The deposit is 4,000 so P = 4000.

The interest rate is 9.5%

9.5 ÷ 100 = 0.095.

r = 0.095: I = P*r*t*: I = P*r*tl  = 4000*0.095*

(270/365)I = 281.095890410959 I = 281.10

So your answer would be: 281.10
8 0
3 years ago
In the recursive formula an = an−1 + 5, the value of the previous term is represented by
den301095 [7]

Step-by-step explanation:

In the recursive formula an = an−1 + 5

a_n = a_{n-1}+5

Suppose if a_5 is the nth term then previous term is a_4

To get the previous term we need to subtract 1 from the n

So a_n is the nth term

a_{n-1} is the previous term

Here 5 represents the common difference between two terms

So value of previous term is represented by

a_{n-1}

Answer : a_{n-1}

6 0
3 years ago
A rectangular prism has a volume of 100 cm3. The length of the prism 25 cm, the height is 2 cm, but the width is unknown. What i
Tanya [424]

Answer:

w = 2 cm

Step-by-step explanation:

100 = 25 x 2 x w

w = 2 cm

7 0
2 years ago
The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g
Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

Step-by-step explanation:

This is a problem of the <em>distribution of sample means</em>. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves <em>normally</em> for samples sizes equal or greater than 30 \\ n \geq 30. Mathematically

\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a <em>normal standard distribution</em>, i.e., a normal distribution that has a population mean \\ \mu = 0 and a population standard deviation \\ \sigma = 1.

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}} [2]

From the question, we know that

  • The population mean is \\ \mu = 88 WPM
  • The population standard deviation is \\ \sigma = 14 WPM

We also know the size of the sample for this case: \\ n = 137 sixth graders.

We need to estimate the probability that a sample mean being greater than \\ \overline{X} = 89.87 WPM in the <em>distribution of sample means</em>. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}

\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}

\\ Z = 1.5634 \approx 1.56

This is a <em>standardized value </em> and it tells us that the sample with mean 89.87 is 1.56<em> standard deviations</em> <em>above</em> the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any <em>cumulative</em> <em>standard normal table</em> available in Statistics books or on the Internet. Of course, this probability is the same that \\ P(\overline{X} < 89.87). Then

\\ P(z

However, we are looking for P(z>1.56), which is the <em>complement probability</em> of the previous probability. Therefore

\\ P(z>1.56) = 1 - P(z

\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

5 0
3 years ago
One hen lays 7 eggs in three days.<br>How many eggs do three hens lay in nine days?​
kramer

Answer:

63 eggs.

Step-by-step explanation:

7 times 3 equals 21, which is the amount of eggs one chicken lays in 9 days. Multiply that by 3, you get 63.

3 0
3 years ago
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