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dsp73
2 years ago
9

Q#33: Tell whether the lines for the pair of the equation are parallel, perpendicular, or neither?

Mathematics
1 answer:
Rashid [163]2 years ago
5 0

Answer:

i think its neither

Step-by-step explanation:


You might be interested in
Based on the polynomial remainder theorem, what is the value of the function when x=−6 ?
Vaselesa [24]
ANSWER

f( - 6) =  10


EXPLANATION

The given function is
f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40

According to the remainder theorem,

f( - 6) = R
where R is the remainder when
f(x)

is divided by
x + 6


We therefore substitute the value of x and evaluate to obtain,

f( - 6) =  { (- 6)}^{4}  + 8 {( - 6)}^{3}  + 10 { (- 6)}^{2}  - 7( - 6)+ 40




f( - 6) =  1296 + 8 ( - 216) + 10 (36) - 7( - 6)+ 40




f( - 6) =  1296  - 1728 + 360  + 42+ 40



This will evaluate to,


f( - 6) =  10


Hence the value of the function when
x =  - 6

is
10



According to the remainder theorem,
10
is the remainder when

f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40
is divided by
x + 6
3 0
3 years ago
Which is greater, 73 percent of 87, or 87 percent of 73?
Drupady [299]
87% of 73 is about 63.51 and 73% of 87 is 60.59 so 87% of 73 is greater
4 0
2 years ago
Read 2 more answers
If Kara's cat weighs 15 pounds and Molly's cat weighs 8 pounds, how much heavier is Kara's cat than Molly's cat? 7
marta [7]

Answer:

7 pounds

Step-by-step explanation:

4 0
2 years ago
Please I need help!! Thank you
Artemon [7]
BD=10 because it is symmetrical to AD.
6 0
2 years ago
certain computer virus can damage any file with probability 35%, independently of other files. Suppose this virus enters a folde
Ksivusya [100]

Answer:

0.623 is the probability that between 800 and 850 files get damaged.

Step-by-step explanation:

We are given the following information:

We treat virus can damage computer as a success.

P( virus can damage computer) = 35% = 0.35

The conditions for normal distribution are satisfied.

By normal approximation:

\mu = np = 2400(0.35) = 840\\\sigma = \sqrt{np(1-p)} = \sqrt{2400(0.35)(1-0.35)} = $$23.36

We have to evaluate probability that between 800 and 850 files get damaged.

P(800 \leq x \leq 850) = P(\displaystyle\frac{800 - 840}{23.36} \leq z \leq \displaystyle\frac{850-840}{23.36}) = P(-1.712 \leq z \leq 0)\\\\= P(z \leq 0.428) - P(z < -1.712)\\= 0.666 - 0.043 = 0.623 = 62.3\%

P(800 \leq x \leq 850) = 62.3\%

0.623 is the probability that between 800 and 850 files get damaged.

8 0
3 years ago
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