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2 years ago

Q#33: Tell whether the lines for the pair of the equation are parallel, perpendicular, or neither?

Mathematics

1 answer:

Rashid [163]2 years ago

5 0

Answer:

i think its neither

Step-by-step explanation:

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Based on the polynomial remainder theorem, what is the value of the function when x=−6 ?

Vaselesa [24]

ANSWER

$f( - 6) = 10$

EXPLANATION

The given function is
$f(x) = {x}^{4} + 8 {x}^{3} + 10 {x}^{2} - 7x + 40$

According to the remainder theorem,

$f( - 6) = R$
where R is the remainder when
$f(x)$

is divided by
$x + 6$

We therefore substitute the value of x and evaluate to obtain,

$f( - 6) = { (- 6)}^{4} + 8 {( - 6)}^{3} + 10 { (- 6)}^{2} - 7( - 6)+ 40$

$f( - 6) = 1296 + 8 ( - 216) + 10 (36) - 7( - 6)+ 40$

$f( - 6) = 1296 - 1728 + 360 + 42+ 40$

This will evaluate to,

$f( - 6) = 10$

Hence the value of the function when
$x = - 6$

is
$10$

According to the remainder theorem,
$10$
is the remainder when

$f(x) = {x}^{4} + 8 {x}^{3} + 10 {x}^{2} - 7x + 40$
is divided by
$x + 6$

3 0

3 years ago

Which is greater, 73 percent of 87, or 87 percent of 73?

Drupady [299]

87% of 73 is about 63.51 and 73% of 87 is 60.59 so 87% of 73 is greater

4 0

2 years ago

Read 2 more answers

If Kara's cat weighs 15 pounds and Molly's cat weighs 8 pounds, how much heavier is Kara's cat than Molly's cat? 7

marta [7]

Answer:

7 pounds

Step-by-step explanation:

4 0

2 years ago

Please I need help!! Thank you

Artemon [7]

BD=10 because it is symmetrical to AD.

6 0

2 years ago

certain computer virus can damage any file with probability 35%, independently of other files. Suppose this virus enters a folde

Ksivusya [100]

Answer:

0.623 is the probability that between 800 and 850 files get damaged.

Step-by-step explanation:

We are given the following information:

We treat virus can damage computer as a success.

P( virus can damage computer) = 35% = 0.35

The conditions for normal distribution are satisfied.

By normal approximation:

$\mu = np = 2400(0.35) = 840\\\sigma = \sqrt{np(1-p)} = \sqrt{2400(0.35)(1-0.35)} = $$23.36$

We have to evaluate probability that between 800 and 850 files get damaged.

$P(800 \leq x \leq 850) = P(\displaystyle\frac{800 - 840}{23.36} \leq z \leq \displaystyle\frac{850-840}{23.36}) = P(-1.712 \leq z \leq 0)\\\\= P(z \leq 0.428) - P(z < -1.712)\\= 0.666 - 0.043 = 0.623 = 62.3\%$

$P(800 \leq x \leq 850) = 62.3\%$

0.623 is the probability that between 800 and 850 files get damaged.

8 0

3 years ago