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Law Incorporation [45]

3 years ago

12

I need to find the median ,mean,mode,range,and

2 answers:

Makovka662 [10]3 years ago

8 0

Median: 23.5
12 and 35 are in the middle so you add them and divide by 2, leaving you
23.5 as your median.
Mean: 41.3
Add all numbers together and divide the sum by the number of numbers added. So all numbers added together equals 413. Divide by ten the nuber of numbers added. 413/10 equals 41.3.
Mode: 99
The number that appears most often. In this case, 99 would be the mode.
Range: 98
The lowest number subtracted from the highest number. 99-1 equals 98.
IQR: 84.75

Hope this helped! :)

Viktor [21]3 years ago

5 0

1, 3, 7, 9, 12, 35, 60, 88, 99, 99

median: 10.5

mean: 1 + 3 + 7 + 9 + 12 + 35 + 60 + 88 + 99 + 99 = 413/10 = 41.3

mode: 99

Range: 99 - 1 = 98

IQR ( interquartile range): 88 - 7 = 81

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Answer:

1) $n = 84$

2) $n = 78$

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Step-by-step explanation:

To solve each proportion, we apply cross multiplication.

Question 1:

$\frac{5}{12} = \frac{35}{n}$

$5n = 35*12$

Simplifying both sides by 5

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Question 2:

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$120n = 52*180$

Simplifying both sides by 20

$6n = 52*9$

Simplifying by 3

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Simplifying by 2

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Question 3:

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Simplifying both sides by 7

$3n = 18*4$

Simplifying both sides by 3

$n = 6*4 = 24$

Question 4:

$\frac{n}{4} = \frac{24}{6}$

$\frac{n}{4} = 4$

$n = 16$

Question 5:

$\frac{10}{16} = \frac{n}{56}$

$16n = 56*10$

Simplifying by 2, both sides

$8n = 56*5$

Simplifying by 8, both sides

$n = 7*5 = 35$

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