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coldgirl [10]
3 years ago
8

an apple farm costs $5 to get in and $0.75 per pound of apples, what is the y intercept? (Number answer only, no symbols)​

Mathematics
2 answers:
velikii [3]3 years ago
8 0
0 then 5 I took the test
Alexeev081 [22]3 years ago
7 0

Answer:

(0, 5).

Step-by-step explanation:

$5 is the base fee, so when x = 0, y = 5. 0.75 won't come into play yet.

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Todd is 81 years younger than Rosa. 3 years ago, Rosa’s age was 4 times Todd’s age. How old is Todd now?
Delvig [45]
Let t represent Todd's age now.
.. 4(t -3) -(t -3) = 81 . . . . . . 3 years ago, their differnce in ages was 81.
.. 3t -9 = 81
.. t = (81 +9)/3 = 30

Todd is 30 now.

_____
You can also work this by considering "ratio units." 3 years ago, the ratio of their ages was 4:1, a difference of 3. That difference corresponds to 81 years, so each "ratio unit" represents 81/3 = 27 years. Todd's age then was 1 ratio unit, 27 years. Now, Todd's age is 30.
8 0
3 years ago
What is the distance between nicholas's school and the post office?
aleksklad [387]
Part A:

Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

d= \sqrt{(-2-3)^2+(-2-2)^2}  \\  \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16}  \\  \\  \sqrt{41} =\bold{6.4} \ units



Part B:

If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:

d= \sqrt{(1-(-3))^2+(-1-2)^2}  \\  \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9}  \\  \\ = \sqrt{16+9} = \sqrt{25} =\bold{5}
4 0
3 years ago
a sphere is circumscribed about an 8-inch by 8-inch by 8-inch cube. Find the volume to the nearest cubic inch.
Anit [1.1K]

The volume of the cube is (8 x 8 x 8)  =  8³  =  <em>512 cubic inches</em>  (exact)


7 0
4 years ago
Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

x_v=-\frac{b}{2a}

In this problem, we have:

y=-x^2-6x-13

Then:

a = -1

b = -6

We write now:

x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
1 year ago
I understand how to find out slope but I need help finding out what to do after that
barxatty [35]
Just look at the line and see how many times it goes up it is just like rise over run it is simple 
8 0
3 years ago
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