Answer:
D. b=7a
Step-by-step explanation:
Add -11/3a to both sides.

Divide both sides by 1/3
1
/3
b
÷1/
3
=
7/
3
÷a
1
/3
and the answer is
b=7a
ik this doesnt make any sense but hope this helps
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
The y intercept is where m=0. Hence, set m=0 and solve for c:
c=0.05(0)+4.95
c=4.95
Answer:
7
Step-by-step explanation:
Answer:
(1252+252)(52−1)
=(1252+252)(52+−1)
=(1252)(52)+(1252)(−1)+(252)(52)+(252)(−1)
=390625−15625+15625−625
=390000
divide by 39 is
=10000