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Morgarella [4.7K]
3 years ago
6

Find the hcf of 120 and 150​

Mathematics
2 answers:
Alexeev081 [22]3 years ago
6 0

Answer: GCF = 30  for the values 120, 150

Step-by-step explanation:

The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

The factors of 150 are: 1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150

Then the greatest common factor is 30.

timofeeve [1]3 years ago
3 0
The highest common factor of 120 and 150 is 30.
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Here's the question. ​
OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is <u>-20</u>.

Step-by-step explanation:

<u>Given</u> :

  • >> If for an A.P, d = -4

<u>To</u><u> </u><u>Find</u> :

  • >> T₂₀ - T₁₅

<u>Using Formula</u> :

General term of an A.P.

\star{\small{\underline{\boxed{\sf{\red{ T_n = a  + (n - 1)d}}}}}}

  • >> Tₙ = nᵗʰ term
  • >> a = first term
  • >> n = no. of terms
  • >> d = common difference

<u>Solution</u> :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{20} = a  + (20 - 1) d}}}

{\dashrightarrow{\sf{ T_{20} = a  + (19)d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19  \times d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19d}}}

{\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a  + 19d}}}}}}

Hence, the value of T₂₀ is a + 19d.

\rule{190}1

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{15}= a  + (15 - 1) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + (14) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14 \times d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14d}}}

{\star{\underline{\boxed{\sf \pink{ T_{15}= a  + 14d}}}}}

Hence, the value of T₁₅ is a + 14d

\rule{190}1

Now, finding the difference between T₂₀ - T₁₅ :

{\dashrightarrow{\pmb{\sf{T_{20} -  T_{15}}}}}

{\dashrightarrow{\sf{(a + 19d) -  (a + 14d)}}}

{\dashrightarrow{\sf{a + 19d -  a  -  14d}}}

{\dashrightarrow{\sf{a - a + 19d -  14d}}}

{\dashrightarrow{\sf{0+ 19d -  14d}}}

{\dashrightarrow{\sf{19d -  14d}}}

{\dashrightarrow{\sf{5 \times  - 4}}}

{\dashrightarrow{\sf{ - 20}}}

{\star \: \underline{\boxed{\sf{\pink{T_{20} -  T_{15} =  - 20}}}}}

Hence, the value of T₂₀ - T₁₅ is -20.

\underline{\rule{220pt}{3.5pt}}

3 0
2 years ago
A boy who is flying a kite lets out 300 feet of string which makes an angle of 60o with the ground. Assuming that the string is
Aleks [24]
<h3><u>Answer</u> :</h3>

See the attachment for better understanding.

<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u>: Length of string (AC) = 300ft

<u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u><u> </u>: Height of the kite from ground (AB)

:\implies\sf\:sin60^{\circ}=\dfrac{AB}{AC}

:\implies\sf\:\dfrac{\sqrt{3}}{2}=\dfrac{H}{300}

:\implies\sf\:H=\dfrac{300\sqrt{3}}{2}

:\implies\sf\:H=150\sqrt{3}

:\implies\:\boxed{\bf{\red{H\approx 260\:feet}}}

Hope it helps !

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3 years ago
Expand.If necessary combine like terms.(1+6x)(1-6x)
Anastaziya [24]

Answer:

-36x^2+1

Step-by-step explanation:

(1+6x)(1-6x)

= 1^2(6x)^2

= -36x^2+1

6 0
3 years ago
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NikAS [45]

Answer:

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Step-by-step explanation:

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Write the equation of a circle given the center (-4, 4) and raduis r = 5.
Len [333]

Answer:

A) (x+4)^2+(y-4)^2=25

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius. If (h,k)\rightarrow(-4,4) and r=5, then:

(x-h)^2+(y-k)^2=r^2\\\\(x-(-4))^2+(y-4)^2=5^2\\\\(x+4)^2+(y-4)^2=25

Therefore, the equation of the circle is (x+4)^2+(y-4)^2=25

6 0
2 years ago
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