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3 years ago

Ryan invested $5,900 in an account paying an interest rate of 5% compounded

Mathematics

2 answers:

Phoenix [80]3 years ago

7 0

Answer:

10214.51

Step-by-step explanation:

vladimir1956 [14]3 years ago

4 0

Answer:

10214.51

Step-by-step explanation:

5900 * (1+ (0.05/12))^(12*11)

please give brainliest

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A square pyramid has a base length of 6 inches. The height of each triangular face is 11 inches. Which expressions correctly cal

VMariaS [17]

Answer:

168 in²

Step-by-step explanation:

The square would be 36 in²

Area of a triangle is A= 1/2 bh

A = 1/2 (11 x 6), A= 1/2 (66)

1/2 (66) = 33 in², which is the area of a triangle.

Then you multiply 33 x 4 to get the area of all the triangles, which is 132 in²

You add the area of the square to the area of the triangles, which is 168 in².

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3 years ago

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Pavlova-9 [17]

Answer: same

Step-by-step explanation:

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3 years ago

The weekly salary of a store manager includes a $30 bonus plus the number of hours the manager works multiplied by the managers

just olya [345]

Answer:

Yes this is a linear function f(x) = ex+30

e = hourly rate

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4 years ago

mark's soup recipe makes 6 servings and uses 4 carrots and 2 potatoes. How many carrots and potatoes does he need for 15 serving

VLD [36.1K]

Let’s see, for 6 servings he needed 4 carrots, meaning every carrot was equal to 1.5 servings. 15/1.5 is 10, 10 carrots for 15 servings.

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3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

4 years ago