Answer:
x= -3 and y = 6
Step-by-step explanation:
so basically what you are trying to do is reduce into finding x and y
what you do is you want to find a number to multiply one of the equations in order to get the same x or y value does not matter which
so,...
we can do
either 20x or 15y
we will go with the smallest 15y
so for both equations multiply the whole thing by 5 for the first equation and by 3 for the second
5 x 5x+3y=3 --> 1
3 x 4x+5y=18 --> 2
we then get
25x+15y = 15 -->1
12x + 15y = 54 -->2
then now that you have the same Y values you can subtract ! which cancels out both the 15y
25x+15y = 15 -->1
- 12x + 15y = 54 -->2
13x =-39
so now x=-3 and all you have to do with x = -3 is sub this into either one of the equations that you started with !
x = -3
5(-3) +3y =3
-15 + 3y = 3
3y = 3+15
3y=18
y = 6!
Answer:
10m=32.8084 foot
Step-by-step explanation:
that's your answer
Answer:
no
Step-by-step explanation:
in less you want a un proportional number
Answer:

Step-by-step explanation:
Let h be the cylinders height and r the radius.
-The volume of a cylinder is calculated as:

-Since the cone is within the cylinder, it has the same radius as the cylinder.
-Let
be the height of the cone.
-The area of a cone is calculated as;

The volume of the solid section of the cylinder is calculated by subtracting the cone's volume from the cylinders:

Hence, the approximate area of the solid portion is 
Answer:
The expected monetary value of a single roll is $1.17.
Step-by-step explanation:
The sample space of rolling a die is:
S = {1, 2, 3, 4, 5 and 6}
The probability of rolling any of the six numbers is same, i.e.
P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = 
The expected pay for rolling the numbers are as follows:
E (X = 1) = $3
E (X = 2) = $0
E (X = 3) = $0
E (X = 4) = $0
E (X = 5) = $0
E (X = 6) = $4
The expected value of an experiment is:

Compute the expected monetary value of a single roll as follows:
![E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17](https://tex.z-dn.net/?f=E%28X%29%3D%5Csum%20x%5Ccdot%20P%28X%3Dx%29%5C%5C%3D%5BE%28X%3D1%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D2%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D3%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%2B%5BE%28X%3D4%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D5%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D6%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%3D%5B3%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B4%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%3D1.17)
Thus, the expected monetary value of a single roll is $1.17.