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Ann [662]
3 years ago
9

A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a

time without replacement. What is the probability that exactly 2 fakes are selected before the second real diamond is selected
Mathematics
1 answer:
Sonja [21]3 years ago
6 0

Answer:

Step-by-step explanation:

The total number of ways of selecting 3 gems of any kind without replacement is 35 * 34 * 33 = 39270

Now selecting 2 gems from 25 is 25C2

25 C 2 = 25 * 24/2 = 300

Selecting one good gem is 10

Total selection = 300 * 10 = 3000

P(gems) = 3000 / 39270

P(gems) = 300/3927

P(gems) = 100/1309

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tester [92]

Given:

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