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2 years ago

HELP giving brainlest and more points

Mathematics

2 answers:

NISA [10]2 years ago

8 0

Answer:

$8^{-5}$

Step-by-step explanation:

$(8^{-8})(8^3)\\8^{-5}$

Exponent equation:

3 - 8 = -5

So this the remaining exponent

Lubov Fominskaja [6]2 years ago

3 0

${8}^{ - 8} \times {8}^{3}$

$( {8})^{ - 8 + 3}$

${8}^{ - 5}$

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Yakvenalex [24]

Hello,

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8 0

3 years ago

15p+3(p-1)>3(2) exponent of 3 on two

Bas_tet [7]

15p + 3(p-1) > 3(2^3)
15p + 3p - 3 > 3(8)
18p - 3 > 24
18p > 24 + 3
18p > 27
p > 27/18
p > 3/2 or 1 1/2

6 0

3 years ago

A particle is projected vertically upwards . It attains a height h after 2 seconds and again after 10 seconds . the height h is

Katena32 [7]

Answer:

320m

Step-by-step explanation:

that is the procedure above

7 0

2 years ago

At what points on the given curve x = 4t3, y = 3 + 40t − 2t2 does the tangent line have slope 1?

dexar [7]

ANSWER

The points are:

(32,-85)

and

$( \frac{500}{27} , \frac{577}{9} )$

EXPLANATION

The given parametric equation that defines the curve is:

$x = 4 {t}^{3}$

$y = 3 + 40t - 2 {t}^{2}$

We differentiate to get,

$\frac{dx}{dt} = 12 {t}^{2}$

$\frac{dy}{dt} = 40 - 4t$

The slope of the tangent is given by;

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }$

$\frac{dy}{dx} = \frac{12 {t}^{2} }{40 - 4t}$

For the slope to be 1, then we must solve the following equation for t.

$\frac{12 {t}^{2} }{40 - 4t} = 1$

$12 {t}^{2} = 40 - 4t$

$12 {t}^{2} + 4t - 4 0 = 0$

$3{t}^{2} + t - 10 = 0$

$(t + 2)(3t - 5) = 0$

$t = - 2 \: \: or \: \: t = \frac{5}{3}$

When t=-2, we put -2 into the expression for x and y to get

x=4(-2)³ and y=3+40(-2)-2(-2)²

This implies that,

x=32, y=-85

Hence one point is (32,-85)

Similarly, when

$t = \frac{5}{3}$

$x = \frac{500}{27} ,y = \frac{577}{9}$

Another point is

$( \frac{500}{27} , \frac{577}{9} )$

7 0

3 years ago

Which set of numbers forms a Pythagorean triple?

egoroff_w [7]

Answer:

3, 4, 5

Step-by-step explanation:

3 ^2 = 9

4 ^2 = 16

5 ^2 = 25

9 + 16 = 25

6 0

2 years ago