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MArishka [77]
3 years ago
8

Given the following data set 2,3,1,6,1,1,1,0,2,4,5,1,2,2,3Mean Median RangeMid range

Mathematics
2 answers:
igomit [66]3 years ago
8 0

Answer:

mean: 34/15=2.27

median: 2

range: highest-lowest...... 6-0=6

mid range: high + low divided by 2

6+0=6/2=3

madreJ [45]3 years ago
4 0

Answer:

Mean: 2.27

Median: 2

Range: 6

Mid-range: 3

Step-by-step explanation:

The mean is adding the average of the data set; add up all numbers, then divide by how many numbers there are.

2 +3 + 1 + 6 + 1 + 1 + 1 + 0 + 2 + 4 + 5 + 1 + 2 + 2 + 3 = 34

There are 15 numbers in this data set.

34 ÷ 15 = 2.26666666667 ≈ 2.27 (nearest hundredth)

2.27 is the mean.

-------------------------------------------------------------------------------------------------------------The median is the middle number after putting the data set in numerical order.

0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 5, 6

The median is 2.

--------------------------------------------------------------------------------------------------------------

0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 5, 6

The range is the smallest number subtracted from the largest number.

6 - 0 = 6

6 is the range.

--------------------------------------------------------------------------------------------------------------

0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 5, 6

The formula for mid-range is:

Maximum value + largest value ÷ 2.

The largest value is 6.

The minimum value is 0.

6 + 0 = 6

6 ÷ 2 = 3.

The mid-range is 3.

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To simplify the calculations, we start by calculating the fourth root of r:

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<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

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We can now calculate for each value of k:

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