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MArishka [77]
3 years ago
8

Given the following data set 2,3,1,6,1,1,1,0,2,4,5,1,2,2,3Mean Median RangeMid range

Mathematics
2 answers:
igomit [66]3 years ago
8 0

Answer:

mean: 34/15=2.27

median: 2

range: highest-lowest...... 6-0=6

mid range: high + low divided by 2

6+0=6/2=3

madreJ [45]3 years ago
4 0

Answer:

Mean: 2.27

Median: 2

Range: 6

Mid-range: 3

Step-by-step explanation:

The mean is adding the average of the data set; add up all numbers, then divide by how many numbers there are.

2 +3 + 1 + 6 + 1 + 1 + 1 + 0 + 2 + 4 + 5 + 1 + 2 + 2 + 3 = 34

There are 15 numbers in this data set.

34 ÷ 15 = 2.26666666667 ≈ 2.27 (nearest hundredth)

2.27 is the mean.

-------------------------------------------------------------------------------------------------------------The median is the middle number after putting the data set in numerical order.

0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 5, 6

The median is 2.

--------------------------------------------------------------------------------------------------------------

0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 5, 6

The range is the smallest number subtracted from the largest number.

6 - 0 = 6

6 is the range.

--------------------------------------------------------------------------------------------------------------

0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 5, 6

The formula for mid-range is:

Maximum value + largest value ÷ 2.

The largest value is 6.

The minimum value is 0.

6 + 0 = 6

6 ÷ 2 = 3.

The mid-range is 3.

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Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

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Nimfa-mama [501]

Answer:

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so the equation would be y= -4x+22

b=y-intercept

mx=slope multiplied by x

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