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maria [59]
3 years ago
9

What is the answer to -43+2x+7x*43

Engineering
1 answer:
aliina [53]3 years ago
5 0

Explanation:

here you go. the answer is 303x+4

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Draw isometric projection of a pls help
Genrish500 [490]

Draw isometric projection Spatial axes of the item are represented as similarly willing to the drawing floor and same distances alongside the axes are drawn the same.

<h3>What is isometric projection?</h3>

Definition of isometric projection an axonometric projection wherein the 3 spatial axes of the item are represented as similarly willing to the drawing floor and same distances alongside the axes are drawn same.

An isometric view of an item may be received via way of means of selecting the viewing path such that the angles among the projections of the x, y, and z axes are all of the same, or 120°. For example, with a cube, that is achieved via way of means of first searching immediately toward one face.

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8 0
2 years ago
How do I quickly learn javascript?
ollegr [7]

Answer:

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3 0
3 years ago
A 100 MHz generator with Vg= 10/00 v and internal resistance 50 ohms air line that is 3.6m and terminated in a 25+j25 ohm load
Lilit [14]

The value of Vz at point z from the generator  = 17.748 ∠ -107.62°  V

<u>Given data :</u>

Internal resistance = 50 ohms

Vg = 10 ∠ 0° v

length of air line = 3.6 m

Terminating resistance = 25 + j25 Ω

<u />

<u>First step : Determine the </u><u>Total impedance </u>

Total Impedance ( z ) = Rin + Rline + Rl + jXl

                                   = 50 + 50 + 25 + j25  

                                   = 125 + j25  ≈ 127.47 ∠ 11.3°

<u></u>

<u>Next step : Determine the </u><u>curren</u><u>t in the circuit </u>

current ( I ) = Vg / z

                  =  ( 10∠0° v ) / ( 127.47 ∠ 11.3° )

                 = 0.0784 ∠ -11.3  amp

<u />

<u>Final step</u><u> : Determine the value of Vz at point z from the generator </u>

Vz = ( Vg + I * Ri ) - ( RI * I + Rline * I )

    = ( 10∠0° + 0.0784 ∠ -11.3  * 50 ) - ( 25 + j25  + 50 * 0.0784 ∠ -11.3 )

    = -5.37 - j16.91  ≈  17.748 ∠ -107.62°  V

Hence we can conclude that the value of Vz at point z form the generator 17.748 ∠ -107.62°  V

Learn more about voltage : brainly.com/question/11288970

Hello your question is incomplete below is the complete question

<u><em>A 100 MHz generator with Vg =10< 0 degree (v) and internal resistance 50-ohm is connected to a lossless 50-ohm air line that is 3.6m long and terminated in a 25+j25 (ohm) load. </em></u>

<u><em> Find (a) V(z) at a location z from the generate.</em></u>

4 0
3 years ago
g a heat engine is located between thermal reservoirs at 400k and 1600k. the heat engine operates with an efficiency that is 70%
Bond [772]

Answer:

<em>Heat rejected to cold body = 3.81 kJ</em>

Explanation:

Temperature of hot thermal reservoir Th = 1600 K

Temperature of cold thermal reservoir Tc = 400 K

<em>efficiency of the Carnot's engine = 1 - </em>\frac{Tc}{Th}<em> </em>

eff. of the Carnot's engine = 1 - \frac{400}{600}

eff = 1 - 0.25 = 0.75

<em>efficiency of the heat engine = 70% of 0.75 = 0.525</em>

work done by heat engine = 2 kJ

<em>eff. of heat engine is gotten as = W/Q</em>

where W = work done by heat engine

Q = heat rejected by heat engine to lower temperature reservoir

from the equation, we can derive that

heat rejected Q = W/eff = 2/0.525 = <em>3.81 kJ</em>

6 0
3 years ago
A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of wid
dmitriy555 [2]

Complete Question:

A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of width 5mm and a depth of cut of 0.5 mm. Estimate the minimum time required to reduce the depth of the plate by 20 mm if the tool moves at 400 mm per second.

Answer:

T_{min} = 26 mins 40 secs

Explanation:

Reduction in depth, Δd = 20 mm

Depth of cut, d_c = 0.5 mm

Number of passes necessary for this reduction, n = \frac{\triangle d}{d_c}

n = 20/0.5

n = 40 passes

Tool width, w = 5 mm

Width of metal plate, W = 200 mm

For a reduction in the depth per pass, tool will travel W/w = 200/5 = 40 times

Speed of tool, v = 100 mm/s

Time/pass = \frac{40*400}{400} \\Time/pass = 40 sec

minimum time required to reduce the depth of the plate by 20 mm:

T_{min} = number of passes * Time/pass

T_{min} = n * Time/pass

T_{min} = 40 * 40

T_{min} =  1600 = 26 mins 40 secs

3 0
4 years ago
Read 2 more answers
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