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Arte-miy333 [17]

3 years ago

11

Provide two programming examples in which multithreading provides better performance than a single-threaded solution. Provide on

e example where singlethreaded solution performs better than multi-threaded solution

1 answer:

Kobotan [32]3 years ago

5 0

Answer:

I dont kno

Explanation:

Im so sorry

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What to you do if you have a flat tirer

Vika [28.1K]

Answer: change the tires

Explanation: you can’t drive on a flat tire

6 0

3 years ago

torisob [31]

Answer:

C). rearview mirror (at least of four inches by four inches).

Explanation:

<u>A 'rearview mirror' would be needed in case one is required to pull an individual on water skis after a PWC(personal watercraft) that is rated for carrying two persons only</u>. This wide-angle mirror for rearview would allow the operator to monitor the person who is being towed constantly along with riding the ski at the same time. It is considered illegal to tow a person on a vessel without having a rearview mirror and at the same time, the limited capacity must also be followed strictly. Hence, <u>option C</u> is the correct answer.

7 0

3 years ago

River models are used to study many different types of flow situations. A certain small river has an average width and depth of

slavikrds [6]

Answer: 7ft x21 I’d be right but yes I am

Explanation: because it is Welty

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3 years ago

A long rod of 60-mm diameter and thermophysical properties rho= 8000 kg/m3, c= 500 J/kg·K, and k= 50 W/m·K is initially at a uni

Dvinal [7]

Answer:

Tc = = 424.85 K

Explanation:

Data given:

D = 60 mm = 0.06 m

$\rho = 8000 kg/m^3$

k = 50 w/m . k

c = 500 j/kg.k

$h_{\infty} = 1000 w/m^2$

$t_{\infity} = 750 k$

$t_w = 500 K$

$surface area = As = \pi dL$

$\frac{As}{L} = \pi D = \pi \timeS 0.06$

HEAT FLOW Q is

$Q = h_{\infty} As (T_[\infty} - Tw)$

$= 1000 \pi\times 0.06 (750-500)$

= 47123.88 w per unit length of rod

volumetric heat rate

$q = \frac{Q}{LAs}$

$= \frac{47123.88}{\frac{\pi}{4} D^2 \times 1}$

$q = 1.66\times 10^{7} w/m^3$

$Tc = \frac{- qR^2}{4K} + Tw$

$= \frac{ - 1.67\times 10^7 \times (\frac{0.06}{2})^2}{4\times 56} + 500$

= 424.85 K

7 0

3 years ago

Calculate the mean and median of the following

AfilCa [17]

Answer:

mean:24/5

ascending order:1,2,3,4,5,5,6,6,7,9

median:5

8 0

3 years ago