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Arte-miy333 [17]
3 years ago
11

Provide two programming examples in which multithreading provides better performance than a single-threaded solution. Provide on

e example where singlethreaded solution performs better than multi-threaded solution
Engineering
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

I dont kno

Explanation:

Im so sorry

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What are the general principles of DFA? What are the steps to minimize the number of parts for an assembly?
BigorU [14]

Answer Explanation : The general principles for design for assembly (DFA) are,

  • MINIMIZE NUMBER OF COMPONENT
  • USE STANDARD COMMERCIALLY AVAILABLE COMPONENTS
  • USE COMMON PARTS ACROSS PRODUCT LINES
  • DESIGN FOR EASE OF PART FABRICATION
  • DESIGN PARTS WITH TOLERANCE THAT ARE WITHIN PROCESS CAPABILITY
  • MINIMIZE USE OF FLEXIBLE COMPONENT
  • DESIGN FOR EASE OF ASSEMBLY
  • USE MODULAR DESIGN
  • REDUCE ADJUSTMENT REQUIRED

STEPS TO MINIMIZE THE NUMBER OF PARTS

  • USE OF INCORPORATE HINGS
  • USE OF INTEGRAL SPRINGS
  • USE OF SNAP FITS
  • USE OF GUIDES BEARINGS
  • USE OF COVERS

6 0
3 years ago
The occupants of a remote village rely exclusively on a single micro hydro facility for all of their electricity needs. The hydr
nordsb [41]

Answer:

In summer the power available is 357.55 kW and in winter the power available is 59.59 kW

Explanation:

Given data:

height = 1500 ft = 457.2 m

30 gallon = 0.114 m³

5 gallon = 0.019 m³

In summer the power available is:

P=\mu \rho ghQ

Where

μ = efficiency = 0.7

ρ = density of water = 1000 kg/m³

g = gravity = 9.8 m/s²

Q = 0.114 m³

Replacing:

P=0.7*1000*9.8*457.2*0.114=3.575x10^{5} W=357.55kW

In winter the power available is

P=0.7*1000*9.8*457.2*0.019=59591.45W=59.59kW

6 0
3 years ago
Para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al
padilas [110]

Answer:

Se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.

Explanation:

Dado que para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al vacío, y en el evaporador se elimina el agua necesaria para que el jugo salga con una concentración del 60% de peso de sólidos, si se introducen al proceso 1000 kg/h de jugo diluido, para calcular la cantidad de agua evaporada y de jugo concentrado saliente se debe realizar el siguiente cálculo;

1000 x 0.07 = 70

60 = 70

100 = X

100 x 70 / 60 = X

7000 / 60 = X

116.66 = X

Por lo tanto, se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.

4 0
3 years ago
The function below takes a two parameters: a list called a_list and a value called a_value. Complete the function to first check
Alik [6]

Explanation:

def checklist(a_list, a_value):// def //used to name a function, the //arguments being passed into the //functions are a_list and a_value

if a_value in list://if statement to

//check if it's in the list or not

print("")//print statement to do

//nothing

else://else statement for if the

//a_value is in a_list

a_list.append(a_value)//this adds

//the value to the list

5 0
3 years ago
2. A thin vertical panel L = 3 m high and w = 1.5 m wide is thermally insulated on one side and exposed to a solar radiation flu
n200080 [17]

Answer: 383.22K

Explanation:

L = 3m, w = 1.5m

Area A = 3 x 1.5 = 4.5m2

Q' = 750W/m2 (heat from sun) ,

& = 0.87

Q = &Q' = 0. 87x750 = 652.5W/m2

E = QA = 652.5 x 4.5 = 2936.25W

T(sur) = 300K, T(panel) = ?

Using E = §€A(T^4(panel) - T^4(sur))

§ = Stefan constant = 5.7x10^-8

€ = emmisivity = 0.85

2936.25 = 5.7x10^-8 x 0.85 x 4.5 x (T^4(panel) - 300^4)

T(panel) = 383.22K

See image for further details.

5 0
3 years ago
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