Answer Explanation : The general principles for design for assembly (DFA) are,
- MINIMIZE NUMBER OF COMPONENT
- USE STANDARD COMMERCIALLY AVAILABLE COMPONENTS
- USE COMMON PARTS ACROSS PRODUCT LINES
- DESIGN FOR EASE OF PART FABRICATION
- DESIGN PARTS WITH TOLERANCE THAT ARE WITHIN PROCESS CAPABILITY
- MINIMIZE USE OF FLEXIBLE COMPONENT
- DESIGN FOR EASE OF ASSEMBLY
- USE MODULAR DESIGN
- REDUCE ADJUSTMENT REQUIRED
STEPS TO MINIMIZE THE NUMBER OF PARTS
- USE OF INCORPORATE HINGS
- USE OF INTEGRAL SPRINGS
- USE OF SNAP FITS
- USE OF GUIDES BEARINGS
- USE OF COVERS
Answer:
In summer the power available is 357.55 kW and in winter the power available is 59.59 kW
Explanation:
Given data:
height = 1500 ft = 457.2 m
30 gallon = 0.114 m³
5 gallon = 0.019 m³
In summer the power available is:
Where
μ = efficiency = 0.7
ρ = density of water = 1000 kg/m³
g = gravity = 9.8 m/s²
Q = 0.114 m³
Replacing:
In winter the power available is
Answer:
Se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.
Explanation:
Dado que para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al vacío, y en el evaporador se elimina el agua necesaria para que el jugo salga con una concentración del 60% de peso de sólidos, si se introducen al proceso 1000 kg/h de jugo diluido, para calcular la cantidad de agua evaporada y de jugo concentrado saliente se debe realizar el siguiente cálculo;
1000 x 0.07 = 70
60 = 70
100 = X
100 x 70 / 60 = X
7000 / 60 = X
116.66 = X
Por lo tanto, se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.
Explanation:
def checklist(a_list, a_value):// def //used to name a function, the //arguments being passed into the //functions are a_list and a_value
if a_value in list://if statement to
//check if it's in the list or not
print("")//print statement to do
//nothing
else://else statement for if the
//a_value is in a_list
a_list.append(a_value)//this adds
//the value to the list
Answer: 383.22K
Explanation:
L = 3m, w = 1.5m
Area A = 3 x 1.5 = 4.5m2
Q' = 750W/m2 (heat from sun) ,
& = 0.87
Q = &Q' = 0. 87x750 = 652.5W/m2
E = QA = 652.5 x 4.5 = 2936.25W
T(sur) = 300K, T(panel) = ?
Using E = §€A(T^4(panel) - T^4(sur))
§ = Stefan constant = 5.7x10^-8
€ = emmisivity = 0.85
2936.25 = 5.7x10^-8 x 0.85 x 4.5 x (T^4(panel) - 300^4)
T(panel) = 383.22K
See image for further details.
