Iven & Find: Compare the average heat transfer coefficients for three different fluids. In all cases the length of the plate
is 1.6 m and the freestream velocity is 1 m/s moving parallel to the plate. Evaluate fluid properties at P = 1 atm and T = 300K. Each of the cases involves a different fluid
i) air,
ii) helium, and
iii) water. Fill in the table of properties for each of the fluids as you will need them in the calculations. Comment on the results.
i) air,
ii) helium, and
iii) water. Fill in the table of properties for each of the fluids as you will need them in the calculations. Comment on the results.
1 answer:
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Answer:
Explanation:
z = number of atoms
M = Molar mass of zirconium
N = Avogadro’s number
Vc = volume of zirconium unit cell
d = density
z = 6 atoms per unit cell
M = 91.224 g/mol
N =
d =
Answer:
Heat required =7126.58 Btu.
Explanation:
Given that
Mass m=20 lb
We know that
1 lb =0.45 kg
So 20 lb=9 kg
m=9 kg
Ice at -15° F and we have to covert it at 200° F.
First ice will take sensible heat at up to 32 F then it will take latent heat at constant temperature and temperature will remain 32 F.After that it will convert in water and water will take sensible heat and reach at 200 F.
We know that
Specific heat for ice
Latent heat for ice H=336 KJ/kg
Specific heat for ice
We know that sensible heat given as
Heat for -15F to 32 F:
Q=858.69 KJ
Heat for 32 Fto 200 F:
Q=6330.74 KJ
Total heat=858.69 + 336 +6330.74 KJ
Total heat=7525.43 KJ
We know that 1 KJ=0.947 Btu
So 7525.43 KJ=7126.58 Btu
So heat required to covert ice into water is 7126.58 Btu.