2 years ago

Log a=6 log b=4 log c=-6 log c^9/√a^3 b

Mathematics

1 answer:

ad-work [718]2 years ago

4 0

Step-by-step explanation:

Log C^9/a ^(3/2) b=

Log c^9 - (Log a^3/2 + Log b)

9Log C - 3/2Log a - Log b

9*-6 - (3/2 * 6) - 4

-54 - 9 - 4

-67

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The <em>equation </em>of a parabola of vertex (h,k) and focus (0,f) is given by:

$y = 4p(x - h)^2 + k^2$

Vertex at the origin means that $h = 0, k = 0$ .
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Thus, the equation of the parabola is:

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$y = 4(6)(x - 0)^2 + 0^2$

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A similar problem is given at brainly.com/question/15165354

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