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3 years ago

Log a=6 log b=4 log c=-6 log c^9/√a^3 b

Mathematics

1 answer:

ad-work [718]3 years ago

4 0

Step-by-step explanation:

Log C^9/a ^(3/2) b=

Log c^9 - (Log a^3/2 + Log b)

9Log C - 3/2Log a - Log b

9*-6 - (3/2 * 6) - 4

-54 - 9 - 4

-67

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Read 2 more answers

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Answer:

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Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

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Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

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$\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%$

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

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$\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%$

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