That would be 177.5 in standard form.
<span>This is true. Because we don’t have more precision our of 6.3, we cannot append more digits with any certainty. We must omit the digit in the hundredths place in order to have a solutionwith correct precision using significant figures.</span>
Answer:
The points would be: (-3, 3) (-4, -1) (2, -1) (1, 3)
Step-by-step explanation:
Because when you move 4 units left, all of the x values in the points will go down by 4, and when you move 2 units down, the y values will go down by 2 units. So when applied to the points shown, you get the answer I put.
I believe this is correct? Hope it helps!
Answer: 0.96875
Step-by-step explanation:
Probability of obtaining at least one tail on a toss of coin 5 times ;
P(success) in a coin toss = 1/2 = 0.5
Using the binomial distribution formula :
P(x) = nCx * p^x * (1 - p)^(n-x)
P(at least one tail) = 1 - p(0 tails)
P( 0 tails) = 5C0 * 0.5^0 * 0.5^(5-0)
= 1 * 1 * 0.03125
= 0.03125
P(at leat 1 tail) = 1 - 0.03125
P(atleast 1 tail) = 0.96875
Well this is kind of difficult because we have no way to determine a constant for each banana; however, we can still formulate an equation to form some sort of solution.
Divide both sides by two:
Now, we can continue to go forward as long as know how many pounds each banana bunch weighs and how many bananas are in the bunch.
We could say there are "x" bananas in each pound of bananas:
Or:
Or to isolate "c":