Answer: D relative humidity
Explanation: Just took the test.
Answer a:
<span>A 1.5 V battery, the electromagnet picked up an average of 6 paper clips, while with the 6.0 V battery, an average of 23 paper clips were picked up. Battery of 6.0V is 6.0/1.5 = 4 times stronger than battery of 1.5 V
Answer b:
</span><span>Ratio of the number of paper clips picked up using the 6.0 V battery to the number picked up using the 1.5 V battery is = 23/6 = 3.8 </span>≈ 4.
Answer c:
As the voltage power increase, more paper clips were picked up by electromagnet. This indicated that there is a direct relationship. Mathematically it can be expressed as:
Voltage Power α Number of paper clips that were picked up
Electron configuration is the electron distribution in the molecular and atomic orbital. An element with configuration ns²np¹ will be in the 3A group. Thus, option B is correct.
<h3>What is electronic configuration?</h3>
The electronic configuration has been the arrangement and distribution of the sub-atomic particle, an electron in the atomic shells.
The electronic configuration given is, ns²np¹. Here, there are three valence electrons in the outermost orbit. As it has been known that the number of the valence electron gives the number of the group.
Therefore, option B. 3A group or 13 group is the correct option.
Learn more about electronic configuration here:
brainly.com/question/11182760
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Your question is incomplete, but most probably your full question was, An element with the general electron configuration for its outermost electrons of ns2np1 would be in which group?
a. 2a
b. 3a
c. 4a
d. 5a
e. 8a
Answer:
Hi, what are the problems on the lab?
Explanation:
Answer:
5.158 mol/L
Explanation:
To find the molarity, you need to use the formula:
Molarity (M) = moles / volume (L)
You have been grams sodium carbonate. You need to (1) convert grams Na₂CO₃ to moles (via molar mass), then (2) convert moles Na₂CO₃ to moles HCl (via mole-to-mole ratio from equation), then (3) convert mL to L (by dividing by 1,000), and then (4) use the molarity equation.
<u>Steps 1 - 2:</u>
2 HCl + 1 Na₂CO₃ ----> 2 NaCl + H₂O + CO₂
6.5287 g Na₂CO₃ 1 mole 2 moles HCl
-------------------------- x ------------- x ------------------------- = 0.12318 mole HCl
106 g 1 mole Na₂CO₃
<u>Step 3:</u>
23.88 mL / 1,000 = 0.02388 L
<u>Step 4:</u>
Molarity = moles / volume
Molarity = 0.12318 mole / 0.02388 L
Molarity = 5.158 mole/L
**mole/L is equal to M**
