Ask question

Ask question

All categories

Marta_Voda [28]

3 years ago

13

Sonia Oopsmeyer, who is proud of how fast she can punch numbers into her calculator, divided a number by 40 instead of multiplyi

ng it by 40. Her answer, which was wrong, was 20. What is the correcr answer? Describe the steps you took to find the correct answer.

1 answer:

VMariaS [17]3 years ago

5 0

Answer:

320

Step-by-step explanation:

x is the mystery number

x÷40=20

20x40=80

80=x

80x40=320

hope this helps

You might be interested in

Anyone wanna help with this iready question?

Illusion [34]

Answer:

3 ticket = 21 $

5 ticket = 35$

so 1 ticket = 7$

9 ticket = 63$

2$ discount

total amount = 61$

Mark my answer as brainlist answer.

7 0

3 years ago

Solve the equation. –4y + 8 = 4(2y – 2) + 4(8 - 2y)

ss7ja [257]

-Y+2=(2y-2)+(8-2y) @
Y=-4

4 0

3 years ago

Read 2 more answers

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

4 years ago

in a class of 37 students,the number of students who like martial art only is double than the number of students who like athlet

yulyashka [42]

Answer:

number of students who like Athletics only = x = 10 students

number of students who like marshal arts only = 2x = 20 students

Step-by-step explanation:

In a class of 37 students, the number of students who like marshal arts only is

double than the number of students who like athletics only. If 3 students like both

and 4 like none of the games, find out how many students like:

i. Marshal arts

ii. Athletics

Total students in the class = 37

number of students who like Athletics only = x

number of students who like marshal arts only = 2x

Number of students who like both = 3

Number of students who like none = 4

Total = athletics + marshal art + both + none

37 = x + 2x + 3 + 4

37 = 3x + 7

37 - 7 = 3x

30 = 3x

x = 30/3

x = 10

number of students who like Athletics only = x = 10 students

number of students who like marshal arts only = 2x

= 2(10)

= 20 students

5 0

3 years ago

How can I write 20,484,163 in expanded from

Leokris [45]

20,000,000+400,000+80,000+4000+100+60+3

8 0

3 years ago

Read 2 more answers