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ki77a [65]
2 years ago
14

The ears of the deer are long and eyes are on the side of the head because? ​

Chemistry
1 answer:
umka21 [38]2 years ago
7 0

If i am going to be honest with you ,in my own humble opinion without being sentimental of course, without offending anyone who thinks differently from my own point of view,but also by looking into this matter in distinctive perspective i would like to say i have nothing to say

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I need help please ASAP
nalin [4]

Answer:

A

Explanation:

because CO2 is carbon dioxide and CO is carbon monoxide. mono meaning one which in this case is monoxide.

6 0
3 years ago
Suggest a way to keep a parked car cool on a sunny day/
Paraphin [41]

Answer:

Crack the windows

Explanation:

believe it or not, one researcher actually tested this back in the 1980s: A study in Pediatrics found that cracking the window 5 centimeters lowered the temperature in a car by about 28°F on a 98°F day .

7 0
2 years ago
What is a way of transforming energy by exerting a force over distance?
xz_007 [3.2K]

Answer:

a. Work

Explanation:

If you apply a force over a given distance - you have done work. Work = Change in Energy. If an object's kinetic energy or gravitational potential energy changes, then work is done. The force can act in the same direction of motion.

8 0
3 years ago
Read 2 more answers
How much heat is gained when a 50.32g piece of aluminum is heated from 9.0°c to 16°c
Rashid [163]

Answer: 317 joules

Explanation:

The quantity of heat energy (Q) gained by aluminium depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of aluminium = 50.32g

C = 0.90J/g°C

Φ = (Final temperature - Initial temperature)

= 16°C - 9°C = 7°C

Then, Q = MCΦ

Q = 50.32g x 0.90J/g°C x 7°C

Q = 317 joules

Thus, 317 joules of heat is gained.

5 0
3 years ago
Read 2 more answers
The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
3 years ago
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