Answer: -
3.3° C
Explanation: -
Mass of water m = 180.5 g
Energy released as heat Q = 2494 J
Specific heat is defined as the heat required to raise the temperature of the unit mass of a given substance by 1 C.
Specific heat of water Cp = 4.184 (J/g)⋅∘C
Using the formula
Q = m x Cp x ΔT
We get temperature change ΔT = Q / (m x Cp)
= 2494 J / ( 180.5 g x 4.184 (J/g)⋅∘C
= 3.3° C
Thus the temprature change, (ΔT), of the wateris 3.3 °C if 180.5 g of water sat in the copper pipe from part A, releasing 2494 J of energy to the pipe
Bynari means that the compound is formed by two kind of elements.
You have listed three ions, V 5+, Cl - and O 2-.
Binary ionic compounds are formed by a positive ion and a negative ion, so the possible ionic compound formed by the listed ions are:
1) VCl5, where the number 5 next to Cl is a subscript.
2) V2O5, where the number 2 next to V and the number 5 next to O are subscripts.
Subscripts are used to indicate the number of atoms of each element in the formula.
So, the empirical formula searched are VCl5 and V2O5.
I can give you other examples with more ions.
Ca (2+) and S(2-) => Ca2S2 => CaS
Na(+) and F(-) => NaF
Cs(+) and Br(-) => CsBr
Answer:
A
both forms of energy referred to in the question is light and heat energy
light energy is the visible energy that travels at a known constant speed of 3.0×10^9m/s
while heat energy is the invisible energy that travels in form of radiation at variable speeds
<u>Answer:</u> The final temperature of the coffee is 43.9°C
<u>Explanation:</u>
To calculate the final temperature, we use the equation:

where,
q = heat released = 
m = mass of water = 10.0 grams
C = specific heat capacity of water = 4.184 J/g°C
= final temperature = ?
= initial temperature = 20°C
Putting values in above equation, we get:

Hence, the final temperature of the coffee is 43.9°C
C - straight line
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