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Degger [83]
3 years ago
14

I need help please anyone can help me !!!!

Mathematics
1 answer:
marta [7]3 years ago
8 0

Answer:

5.15

Step-by-step explanation:

I hope this helps have a great day

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natali 33 [55]

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a m not with math dry buddy hope u find somebody to help pu

5 0
3 years ago
The dot plots below show the scores for a group of students who took two rounds of a quiz:
Anna [14]
C) Round 1 scores were higher than round 2

Mark with crown please!
8 0
3 years ago
Read 2 more answers
Which statement best describes (3 x 4 x6 = 3 x (4 x 6)
Ratling [72]

Answer:

The given statement is,

(3 * 4) * 6 = 3(4 * 6)

To find (3 * 4) * 6

(3 * 4) * 6 = 12 * 6 = 72

To find 3(4 * 6)

3(4 * 6) = 3 * 24 = 72

Step-by-step explanation:

The result of these two expression is same.

Therefore we can conclude that,

Therefore the correct answer is,

The grouping of the factors is changed but the product is the same.

BRAINLIEST ME PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE

7 0
2 years ago
#2) Jane wants to have a test average of at least 78.
Vlad [161]
She would have to score atleast a 74 on the test for her average to be 78
5 0
3 years ago
Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

So the integral of f(x,y,z)=x^2+y^2+z^2 is

\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

6 0
3 years ago
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