Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
Answer:
AB = 21
Step-by-step explanation:
So we have two triangles (AEB and ADC), and they're similar by AA
Now, you can find the ratio of similitude by checking AE/AD which is 14/26 = 7/13
AB/AC = 7/13
Take AB as x aight
x/x+18 = 7/13
x=21
First you want to divide $90 by four. You want to take the answer and divide it by 2.
$90 / 4 = $22.5
22.5 / 2 = Mrs. Jackson saved $11.25.
<h3>
Answer: 944 dollars for the week</h3>
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Explanation:
He sold $4950 worth of items. Take 12% of this amount to get
12% of 4950 = 0.12*4950 = 594
So he earns $594 in commission on top of the $350 base salary paid every week. In total, he earns 594+350 = 944 dollars for that week
This isn't the per week pay because he would need to sell exactly $4950 worth of goods each week to keep this same weekly pay.
Let's solve ~
It's factorized now ~ And if you want to find the zeros then equate the expression with 0.
And you will get ;
