Answer:
it depend on the question but if it is asking if they have the same answer then it is true
Step-by-step explanation:
Answer:
30625
Step-by-step explanation:
Answer:
2 an ? Im pretty sure hope it helped
Step-by-step explanation:
Given that,
Point estimate = sample mean = \bar x = 32.9
sample standard deviation = s = 12.1
sample size = n = 114
Degrees of freedom = df = n - 1 = 114 - 1 = 113
a) t distribution,
b) At 90% confidence level
\alpha = 1 - 90%
\alpha =1 - 0.90 =0.10
\alpha/2 = 0.05
t\alpha/2,df = t0.05,113 = 1.658
Margin of error = E = t\alpha/2,df * (s /\sqrtn)
= 1.658 * (12.1 / \sqrt 114 )
Margin of error = E = 1.879
The 90% confidence interval estimate of the population mean is,
T ± E
= 32.9 ± 1.879
= ( 31.021, 34.779 )
With 90% confidence the population mean minutes of concentration is between 31.021 and 34.779 minutes.
c) If many groups of 114 randomly selected members are studied, then a different confidence interval would be produced from each group. About 90 percent of these confidence intervals will contain the true population mean minutes of concentration and about 10 percent will not contain the true population mean minutes of concentration.
