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Anna71 [15]
3 years ago
14

Ammonium phosphate is an important ingredient in many solid fertilizers. it can be made by reacting aqueous phosphoric acid with

liquid ammonia. calculate the moles of ammonium phosphate produced by the reaction of 0.085 mol of ammonia. be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Chemistry
1 answer:
Debora [2.8K]3 years ago
3 0

Answer:

0.028 mole of ammonium phosphate, (NH₄)₃PO₄.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₃PO₄ + 3NH₃ —> (NH₄)₃PO₄

From the balanced equation above,

3 moles of NH₃ reacted to produce 1 mole of (NH₄)₃PO₄.

Finally, we shall determine the number of mole of (NH₄)₃PO₄ produced by the reaction of 0.085 mole of ammonia, NH₃. This can be obtained as follow:

From the balanced equation above,

3 moles of NH₃ reacted to produce 1 mole of (NH₄)₃PO₄.

Therefore, 0.085 mole of NH₃ will react to produce = (0.085 × 1)/3 = 0.028 mole of (NH₄)₃PO₄.

Thus, 0.028 mole of ammonium phosphate, (NH₄)₃PO₄ were obtained from the reaction.

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Answer:

The answer is no.

Explanation:

The surface of earth does not always stay the same as we know earth constantly moves and the surface of earth is constantly remodeled by various geological processes.

6 0
3 years ago
What is the relative humidity if the dry bulb temperature is 16°C and the wet bulb temperature is 16°C?
Vilka [71]
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5 0
3 years ago
A 25.0 ml solution of .0600 M EDTA was added to a 57.0 ml sample containing an unknown concentration of V3+. All V3+ present for
Rom4ik [11]

Explanation:

Let us assume that the ratio for the given reaction is 1:1.

Therefore, we will calculate the moles of Ga^{3+} as follows.

   Moles of Ga^{3+} solution = molarity × volume (L)

                              = 0.0440 M × 0.014 L

                              = 0.000616 moles

Moles of excess EDTA = 0.000616 moles

Also, the initial moles of EDTA will be calculated as follows.

     Total initial moles of EDTA = 0.0600 M × 0.025 L

                                                 = 0.0015

Therefore, moles of EDTA reacted with V^{3+} will be as follows.

                = 0.0015 - 0.000616

                = 0.00088 moles

Since, we have supposed a 1 : 1 ratio between V^{3+} and EDTA .

So, moles of V^{3+} = 0.00088 moles

Now, we will calculate the molarity of V^{3+} as follows.

       Molarity of V^{3+} solution = \frac{\text{moles}}{\text{volume (L)}}

                             = \frac{0.00088 moles}{0.057 L}

                             = 0.015 M

Thus, we can conclude that the original concentration of the V^{3+} solution is 0.015 M.

4 0
3 years ago
If you collect 1.75 L of hydrogen gas during a lab experiment when the room temperature is 23oC and the barometric pressure is 1
ziro4ka [17]

Answer:

n=0.0747mol

Explanation:

Hello,

In this case, since we can consider hydrogen gas as an ideal gas, we check the volume-pressure-temperature-mole relationship by using the ideal gas equation:

PV=nRT

Whereas we are asked to compute the moles given the temperature in Kelvins, thr pressure in atm and volume in L as shown below:

n=\frac{105kPa*\frac{0.009869atm}{1kPa}*1.75L}{0.082\frac{atm*L}{mol*K}*(23+273.15)K} \\\\n=0.0747mol

Best regards.

8 0
3 years ago
How many moles of oxygen are in 8.25g of O?
posledela
8.25 grams of O2 has 0.258 moles of Oxygen. Here's how you figure that out:
Oxygen is one of the 7 diatomic elements, so it is normally O2.
<span>You find it's molar mass (or mass for </span>one mole<span> of it) by adding up two of the masses from the Periodic Table.</span>
6 0
4 years ago
Read 2 more answers
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