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4 years ago

How many moles of oxygen are in 8.25g of O?

2 answers:

6 0

8.25 grams of O2 has 0.258 moles of Oxygen. Here's how you figure that out:
Oxygen is one of the 7 diatomic elements, so it is normally O2.
You find it's molar mass (or mass for one mole of it) by adding up two of the masses from the Periodic Table.

Doss [256]4 years ago

6 0

Answer: 0.531 mole

Explanation:

I mole of Oxygen = 16g

Let x = 8.25g of Oxygen

Hence,

x = (8.25 * 1) / 16 mole

x = 0.531 mole

Therefore, there is 0.531 mole of Oxygen in 8.25g of Oxygen

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Katyanochek1 [597]

Answer:

The answer to your question is V2 = 4.97 l

Explanation:

Data

Volume 1 = V1 = 4.40 L Volume 2 =

Temperature 1 = T1 = 19°C Temperature 2 = T2 = 37°C

Pressure 1 = P1 = 783 mmHg Pressure 2 = 735 mmHg

Process

1.- Convert temperature to °K

T1 = 19 + 273 = 292°K

T2 = 37 + 273 = 310°K

2.- Use the combined gas law to solve this problem

P1V1/T1 = P2V2/T2

-Solve for V2

V2 = P1V1T2 / T1P2

-Substitution

V2 = (783 x 4.40 x 310) / (292 x 735)

-Simplification

V2 = 1068012 / 214620

-Result

V2 = 4.97 l

6 0

3 years ago

In any sample of DNA, the amount of adenine (A) equals the amount of _____.

aivan3 [116]

It is equal to amount of thymine

8 0

3 years ago

Read 2 more answers

The rate for a reaction between reactants l, m, and n is proportional to the cube of [l] and the square of [m]. what is the rate

postnew [5]

Answer
rate =k[l]^3[m]^2

4 0

3 years ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

3 years ago

The teacher in item 10 also needs to order plastic tubing. If each of the 60 students need 750 mm of tubing, what length of tubi

Alex777 [14]

45 m. If each student needs 750 mm of tubing, the teacher should order 45 m of tubing.

a) Find the length in millimetres

Length = 60 students x (750 mm tubing/1 student) = 45 000 mm tubing

b) Convert millimetres to metres

Length = 45 000 mm tubing x (1 m tubing/1000 mm tubing) = 45 m tubing

6 0

3 years ago