Mass of water required = 64.42 g
<h3>Further explanation</h3>
Given
Reaction
6CO2 + 6H2O → C6H12O6 + 6O2
157.35 g CO2
Required
mass of water
Solution
mol CO₂ = mass : MW CO₂
mol CO₂ = 157.35 g : 44.01 g/mol
mol CO₂ = 3.575
From the equation, mol ratio CO₂ : H₂O = 6 : 6, so mol H₂O = mol CO₂=3.575
Mass H₂O = mol x MW H₂O
mass H₂O = 3.575 x 18.02
mass H₂O = 64.42 g
a) Answer:
= 210,000 gram or 210 Kg
Explanation:
14 hr is equivalent to;
= 14 × 3600 s
But;
8.2x10^4 A = 8.2x10^4 Coulomb /second = 8.2x10^4 C/s
1 Faraday = 96485C
Molar mass of Li: 6.941 g/mol
Therefore;
{(8.2x10^4 C/s)×(14×3600s)×(6.941 g/mol)/(96485C/mol)}×70%
= 2.1x10^5 gram or 210 kg
b. Answer;
= 0.23 kWh/mol
Explanation and solution;
Energy per mole is given by;
(96485C/mol) × (8.4V) = 8.10x10^5 (J/mol)
= 8.10x10^5 (Ws/mol)
Divide by 3600s/h to get:
= 8.10x10^5 (Ws/mol)
= 225 Wh/mol
= 0.23 kWh/mol
I believe the correct factor concerning ionization energy within a period would be that the valence electrons essentially remain at about the same distance from the atomic nucleus when moving from left to right on the periodic table. This is because the Atomic number increases by a value of 1, and depending whether or not the maximum number of electrons are found within the shell, it may have another shell or not.
Oil water corn syrup and honey
Magnesium is more metallic because metallic character decreases across a period