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3 years ago

Draw a square of area 18 square centimetre

Mathematics

1 answer:

Semenov [28]3 years ago

5 0

Answer:

3 $\sqrt{2}\\$ each side

Step-by-step explanation:

make each side 4.24cm or 3 $\sqrt{2}\\$

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Highest common factor of 92 and 42

GarryVolchara [31]

To get the Greates Common Factor (GCF) of 92 and 42 we need to factor each value first and then we choose all the copies of factors and multiply them:

92: 22 2342: 2 37 GCF: 2

The Greates Common Factor (GCF) is: 2

You can always share this solution

8 0

3 years ago

Read 2 more answers

Please help me on my homework! :) Its due tomorrow and I need help on numbers 3-6 thanks ;) (picture attached)

Aleks [24]

3) 0.5(12m-22n)=0.5(12m)-0.5(22n)
=6m-11n
4) 2/3(18x+6z) =2/3(18x)-2/3(6z)
=12x-4z
5)2x+12=2(x+6)
6)12x+24=12(x+2)

7 0

3 years ago

What is the gradient of the blue line, maths watch

Alborosie

No picture? what’s the question

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2 years ago

A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

3 0

3 years ago

Frank says that for any whole number n, the value of 6n-1 is always prime. Is Frank correct? Explain your answer.

Lady bird [3.3K]

Answer:

Frank is wrong

Step-by-step explanation:

$6(6) - 1 = 35$

35 is a multiply by 5 so it is not a prime number.

8 0

3 years ago

Draw a square of area 18 square centimetre​

Draw a square of area 18 square centimetre