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dimaraw [331]
3 years ago
6

Solve. −13(6x−15)+6x>8x−11 A. x −1 C. x 4

Mathematics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

question makes no sense

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20%5Cpi%20%20x%5E%7B2%7D%20" id="TexFormula1" title=" \pi x^{2} " alt=" \pi x^{2} " align="
ANEK [815]

The formule is about area of a circle.

\pi x^{2} = a

We need to solve the equation for x. Where x is the radius of the circle.

In order to solve it for x, we need isolate it for x on left side.

So, first we need to get rid pi from left side.

On dividing both sides by pi, we get

\frac{\pi x^2}\pi}=\frac{a}{\pi}

x^2=\frac{a}{\pi}

Taking square root on both sides, we get

\sqrt{x^2}=\sqrt{\frac{a}{\pi}}

x=\sqrt{\frac{a}{\pi}}


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A

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If A=p+prt, than t equalls?
ella [17]

Answer:

\boxed{t=\frac{A-p}{pr}}

Step-by-step explanation:

A=p+prt

Subtract p on both sides.

A-p=p+prt-p

A-p=prt

Divide both sides by pr.

\displaystyle \frac{A-p}{pr} =\frac{prt}{pr}

\displaystyle{\frac{A-p}{pr} =t}

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3 years ago
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