Using V = ⅓[base area×height]
V= ⅓[ (5.5÷4)² × 2.6]
v= ⅓[ 4.92]
v = 1.6m³
271>249 the greater number is 271 which is two hundred seventy-one
Answer:
Step-by-step explanation:
1. 9x^5
2. 9x^6
3. 27x^5
4. 27x^6
The formula
in solving the integral of the infinity of 3 is ∫3<span>∞?</span>(1<span>)÷((</span>x−2<span><span>)<span><span>(3/</span><span>2)</span></span></span>)</span><span>dx</span>
Substitute the numbers given
then solve
limn→inf∫3n(1/((n−2)(3/2))dn
limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)
=0+2=2
Solve for the integral of 2 when 2 is approximate to 0.
Transpose 2 from the other side to make it -2
∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C
(x−2)−1/2=1x−2−−−−√
0−(3−2)−1/2−1/2=2
<span> </span>
Answer:
1
Step-by-step explanation:
1 : 1 :sqrt(2)
The legs are in the ratio of 1 to 1
tan 45 = opp side / adj side
tan 45 = 1/1
tan 45 =1
