PLEASE HELP ME ITS DUE IN 4 HOURS!!

alukav5142 [94]

91.82 million ft³

Correct answer

5 0

3 years ago

The faces of a tetrahedron die are numbered 1 to 4. if each of the 4 sides is equally likely to land down, what is the probabili

Hoochie [10]

The probability distribution for the face landing down = 4/15

<h3>What is the probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

<h3>According to the given information:</h3>

If we assign 1 probability x

then 2 has probability 1/2 x.

Similarly,

then 3 has probability = 1/2((1/2)*x) = (1/4)*x

so

then 4 has probability = 1/2((1/4)*x) = (1/8)*x

These probabilities need to sum to 1.

Hence:

$x+\frac{1}{2} x+\frac{1}{4} x+\frac{1}{8} x=1$

or equivalently

(15/8)*x = 1

x = 8/15

the probability distribution for the face landing down = (1/2)*(8/15)

= 8/30

= 4/15

To know more about probability visit:

brainly.com/question/1581057

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I understand that the question you are looking for is:

A tetrahedral die has four faces, numbered 1-4. If the die is weighted in such a way that each number is twice as likely to land facing down as the next number (1 twice as likely as 2, 2 twice as likely as 3, and so on) what is the probability distribution for the face landing down?

7 0

2 years ago

Find the volume of L-Blocks

maxonik [38]

To find the volume of L-blocks<span> in each worksheet. To </span>find the volume<span> of a triangular prism, </span>find<span> the area of a triangle and multiply the value with the height of the prism.</span>

8 0

4 years ago

Read 2 more answers

HELP ME OUT PLZZ I WILL GIVE BRAINLISt

BaLLatris [955]

It might be A

Example: I tried to do the math and i came out with 1/20 so try it. i’m very sorry if it’s wrong

4 0

3 years ago

Read 2 more answers

Match the expression on the left with the correct simplified expression on the right.

andriy [413]

Given: The expression below

$\begin{gathered} (\frac{(3x^3y^4)^3}{(3x^2y^2)^2})^2 \\ (\frac{(3x^4y^2)^4}{(3x^5y^2)^3})^2 \end{gathered}$

To Determine: The matching expression to the given expressions

Solution

Let us simplify each of the expressions using exponents rule

$\begin{gathered} Exponent-Rule1=(a^m)^n=a^{m\times n} \\ Exponent-Rule2=(\frac{a^m}{a^n})=a^{m-n} \end{gathered}$

Applying the exponent rule 1 above to the given expressions

$\begin{gathered} (3x^3y^4)^3=3^3x^{3\times3}y^{4\times3}=27x^9y^{12} \\ (3x^2y^2)^2=3^2x^{2\times2}y^{2\times2}=9x^4y^4 \end{gathered}$ $\begin{gathered} (3x^4y^2)^4=3^4x^{4\times4}y^{2\times4}=81x^{16}y^8 \\ (3x^5y^2)^3=3^3x^{5\times3}y^{2\times3}=27x^{15}y^6 \end{gathered}$

Applying the exponent rule 2

$\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}}=\frac{27x^9y^{12}}{9x^4y^4}=\frac{27}{9}x^{9-4}y^{12-4}=3x^5y^8$ $\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}}=\frac{81x^{16}y^8}{27x^{15}y^6}=\frac{81}{27}x^{16-15}y^{8-6}=3xy^2$

Let us not apply exponent rule 1 above

$(\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}})^2=(3x^5y^8)^2=3^2x^{5\times2}y^{8\times2}=9x^{10}y^{16}$ $(\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}})^2=(3xy^2)^2=3^2x^2y^{2\times2}=9x^2y^4$

Hence, the matching is as shown below

8 0

2 years ago