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vekshin1
3 years ago
14

Two pins attracted by a bar magnet maintain a distance between their ends why??​

Physics
1 answer:
pav-90 [236]3 years ago
3 0

Because I like Magnis repeal in opposite magnets attract
You might be interested in
Question 2 (5 points)
d1i1m1o1n [39]

Answer:

Frequency of sound wave = 198.83 hertz (Approx.)

Explanation:

Given:

Velocity of sound wave in air = 340 m/s

Wavelength = 1.71 meter

Find:

Frequency of sound wave

Computation:

Frequency = Velocity / Wavelength

Frequency of sound wave = Velocity of sound wave in air / Wavelength

Frequency of sound wave = 340 / 1.71

Frequency of sound wave = 198.8304

Frequency of sound wave = 198.83 hertz (Approx.)

6 0
3 years ago
a 200 kg crate is pushed horizontally with a force of 700 N. If the coefficient of friction is 0.2 calculate the acceleration of
Crazy boy [7]

Answer:

a=1.54\ m/s^2

Explanation:

<u>Net Force</u>

The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

That acceleration is proportional to the net force and inversely proportional to the mass of the object.

It can be expressed with the formula:

\displaystyle a=\frac{F_n}{m}

Where

Fn = Net force

m  = mass

The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes motion and a horizontal net force appears causing the acceleration.

The forces on the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal:

N = W = mg

The friction force can be calculated by using the coefficient of friction μ:

F_r=\mu N

Calculating the normal force:

N = 200 * 9.8 = 1,960 N

The friction force is:

F_r=0.2*1,960

F_r=392\ N

The horizontal net force is:

F_n = F_a-F_r=700\ N - 392\ N

F_n = 308\ N

Finally, the acceleration is computed:

\displaystyle a=\frac{308}{200}

\boxed{a=1.54\ m/s^2}

3 0
3 years ago
You are sitting on the beach and wondering about the properties of mechanical waves. Describe them in terms of ocean waves.
Rudiy27

Answer:

The ocean waves is a mechanical wave that transmits mechanical energy in the wave by the synchronized and repeated oscillation of the waters about an equilibrium level such that as the wave approaches the shoreline, and the water depth decreases, the height of the wave also increases reflecting the effective transmission of energy while the medium which is the water through which the wave propagates, move back and forth within a small region

Explanation:

A mechanical wave like other waves is the oscillation of a field about an equilibrium level. In mechanical waves, the field consists of the oscillating matter such that the wave transmits energy through a medium. The displacement of the medium through which the wave energy is limited such that the wave energy is conserved to travel far.

7 0
4 years ago
Work occurs when
defon
I believe the answer is the second option.
7 0
4 years ago
A particular person's eardrum is circular, with a diameter of 7.90 mm. How much sound energy (in J) is delivered to an eardrum i
antiseptic1488 [7]

Answer:

4.90167\times 10^{-17}\ J

Explanation:

I = Hearing intensity = 1\times 10^{-12}\ W/m^2

A = Area = \pi r^2

d = Diameter = 7.9 mm

r = Radius = \dfrac{d}{2}=\dfrac{7.9}{2}=3.95\ mm

Power is given by

P=IA\\\Rightarrow P=1\times 10^{-12}\times \pi \times (3.95\times 10^{-3})^2\\\Rightarrow P=4.90167\times 10^{-17}\ W

t = Time the eardrum is exposed to sound = 1 second

Energy is given by

E=Pt\\\Rightarrow E=4.90167\times 10^{-17}\times 1\\\Rightarrow E=4.90167\times 10^{-17}\ J

The energy transferred to the eardrum is 4.90167\times 10^{-17}\ J

3 0
3 years ago
Read 2 more answers
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