A student slides a book across a desk, with a velocity of +8 m/s. When her friend catches the book, it has a velocity of +7.4 m/
s. If the acceleration was a constant -5.6 m/s2, how wide is the desk?
1 answer:
kinematic equation
v^2=u^2+2*a*s
7.4^2=8^2-2*5.6^2*width
(7.4^2-64)/(2*5.6^2)=-width
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