In trigonometry, for a right triangle, the sine (sin) of any angle θ is given as the ratio of its opposite side to the hypotenuse of the triangle, that is, sin θ = (opposite side)/(hypotenuse).

In the question, we are asked to find the trigonometric ratio, sin J, for the given right triangle JKL.

The side opposite to angle J is KL, which has a value of 3 units.

The hypotenuse of the given right triangle is JK, which has a value of 7.8 units.

Thus, sin J can be calculated as:

sin J = KL/JK = 3/7.8 = 5/13 = 0.39.

Thus, in the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

Learn more about trigonometric ratios at

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8 0

1 year ago

Please help with this

omeli [17]

Answer:

$y = \frac{1}{8} x - 3$

Step-by-step explanation:

Formula for straight lines:

$y = mx + b$

where m = slope, b = constant

Given:

y-intercept = -3 (0, -3)

m = ⅛

Substitute into formula to find b.

$- 3 = \frac{1}{8} (0) + b \\ - 3 = 0 + b \\ b = - 3$

Substitute b into original formula

$y = mx + b \\ y = \frac{1}{8} x + ( - 3) \\ y = \frac{1}{8} x - 3$

4 0

2 years ago

Just question # 2 I'll give you 15 points and brainly ​

Just question # 2 I'll give you 15 points and brainly