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9966 [12]
2 years ago
14

What is 1 2/10+8 1/18=

Mathematics
1 answer:
n200080 [17]2 years ago
5 0

Answer: {9}\frac{23}{90}

Step-by-step explanation:

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How do I know when to use Sin, Cos or Tan on Trig Ratios?
Sergio039 [100]

Answer:

Usually in the equation they use Sin, Cos, or tan. Although, If the point in the graph starts at 0 is is sin and anything else would be cos. Tan is the sort of vertical squiggly line.

Step-by-step explanation:

4 0
3 years ago
Can someone help me and tell me the steps plzz​
adell [148]

Answer:

A

Step-by-step explanation:

f(x) = 7x² - 15x + 2

A) f(1) = 7*1² - 15*1 +2 = - 6

f(1.5) = 7*(1.5)² -15*1.5 + 2 = - 4.75

B) f(2.2) = 7*(2.2)²-15*(2.2)+2 = 2.28

C) f(1) = 7*1² - 15*1 +2 = - 6

f(1) = 7*2² - 15*2 +2 = 0

D) not for all real numbers because we already have

f(2.2) = 7*(2.2)²-15*(2.2)+2 = 2.28 that is positive.

5 0
3 years ago
Given parallelogram JKLM, complete the following statements.
Alexxandr [17]

Answer: x= ?

y= 5

mK= 17

mL= 17

ML= 33

Step-by-step explanation:

i dont want to explain but i don’t know what x is i’m sure the rest are right

5 0
3 years ago
I WILL MARK AS BRANLIEST!
PolarNik [594]

Answer:

0.5 pounds is one game

2 pounds is one textbook

Step-by-step explanation:

g = games

t = textbooks

Let's start with how much a game weighs. We know that when Chad added two more games the weight of the box increased by one pound (it was previously 21 pounds and then went to 22 when the two games were added). This means one game equals half of a pound (or 0.5 lbs.)...

2g = 1

\frac{2g}{2} = \frac{1}{2}  -> if you divide one side by two, you must do the same to the other.

g = \frac{1}{2} = 0.5

Now that we know the weight of the games, we can figure out the weight of the textbooks.

6g + 9t = 21 -> 6 games and 9 textbooks weigh 21 pounds.

Plugging in that each game is 0.5 pounds...

6(0.5) + 9t = 21

3 + 9t = 21

3 - 3 + 9t = 21 - 3

9t = 18

\frac{9t}{9} = \frac{18}{9}

t = 2

That means that each textbook equals 2 pounds.

I hope this helps!

8 0
2 years ago
Find the maclaurin series for f(x=sin^2(x
Lilit [14]
Recall that \sin^2x=\dfrac{1-\cos2x}2.

If you know the Maclaurin series for \cos x, finding this expansion should be easy.
4 0
2 years ago
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