Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
(1) circumference of a circle = 2π.R
(2) area of a circle = π.R²
Area = 452.16 m² (given), so we can calculate the radius:
452.16 = π.R²
452.16/π = R²
143.92 = R² → R =√143.92 ≈ 12 m
Having R = 12, now we can calculate the circumference :
circumference of a circle = 2π.R = 2.π.12 = 75.41 m
<span><span><span>−1</span><span>2x</span></span>=<span>−12</span></span><span><span>−1</span>=<span>−<span>24x</span></span></span>(Multiply both sides by 2x)<span><span>−<span>24x</span></span>=<span>−1</span></span>(Flip the equation)<span><span><span>−<span>24x</span></span><span>−24</span></span>=<span><span>−1</span><span>−24</span></span></span>(Divide both sides by -24)<span>x=<span>1<span>24
AND OMG MY CHEMICAL ROMANCE AS YOU PFP!!!!</span></span></span>
Answer:
2.016
Step-by-step explanation:
In your equasion, I couldn't tell if you need to multipy 0.8^2 by 3.15 or are you asking something else? If you want to multiply, the answer is 2.016.
A long time honestly.
roughly around 4 hours i would think
