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enot [183]
3 years ago
12

Which of the following represents a function? OA X -5-1 9 8 -1 y 1 7 23 17 1 B. y NS x -4 NO 4 C. {(0,1),(3,2), (-8,3), (-7,2),

(3,4)} D. -4 5 9 3 13​

Mathematics
1 answer:
gregori [183]3 years ago
5 0

Given:

The different relations in the options.

To find:

The relation which represents a function.

Solution:

A relation is called a function if there exist a unique output (y-value) for each input (x-value).

In option A, there exist two outputs y=7 and y=1 for a single input x=-1. So, this is not a function.

In option B, there exist two outputs y=-5 and y=2 for a single input x=-1. So, this is not a function.

In option C, there exist two outputs y=2 and y=4 for a single input x=3. So, this is not a function.

In option D, there exist only one value of y for each x. So, this is a function.

Therefore, the correct option is D.

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Y = -2x + 2 y = 5x + 9​
WITCHER [35]
X=-1 y=4 hope it helps
8 0
3 years ago
Let f(x) = 12 over the quantity of 4 x + 2 . Find f(−1). (1 point) a −6b −2c 2d 6
antoniya [11.8K]

Answer:

f(-1) = -6

Step-by-step explanation:

f(x) = 12 / ( 4x+2)

Let x = -1

f(-1) = 12 / ( 4*-1+2)

     = 12 / (-4+2)

     = 12 / -2

    = -6

5 0
3 years ago
Consider each equation. is it the equation of the line that is parallel or perpendicular to y=3x+2? Select yes or no for a-c
Mkey [24]

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 2 is in this form with slope m = 3

• Parallel lines have equal slope

• The slopes of perpendicular lines are negative reciprocals of each other

A

y = - \frac{1}{3} x - 8 has slope m = - \frac{1}{3}

3 and - \frac{1}{3} are negative reciprocals

This line is perpendicular to y = 3x + 2

B

y = 3x - 10 has slope m = 3

This line is parallel to y = 3x + 2

C

y = 2x + 4 has slope m = 2

This line is neither parallel nor perpendicular to y = 3x + 2


5 0
3 years ago
Define the function
miss Akunina [59]

Given that

g(x) = x^3 + x

the inverse g^{-1}(x) is such that

g\left(g^{-1}(x)\right) = g^{-1}(x)^3 + g^{-1}(x) = x

or

g\left(f(x)\right) = f(x)^3 + f(x) = x

Differentiating both sides using the chain rule gives

3f(x)^2f'(x) + f'(x) = 1 \\\\ f'(x) \left(3f(x)^2+1\right) = 1 \\\\ f'(x) = \dfrac1{3f(x)^2+1}

Then the derivative of <em>f</em> at 2 is

f'(2) = \dfrac1{3f(2)^2+1} = \boxed{\dfrac14}

7 0
2 years ago
Jane has gone on a diet.She starts with weight of 61kg and loses 2kg every 3 weeks for 12 weeks.she abandoned her diet at the st
andrezito [222]

Answer:

55 kg

Step-by-step explanation:

lose 2kg per 3 week

for 12 weeks

3×4=12

4×2=8

61-8=53

1kg per week gained for 2 weeks = 2kg

53kg + 2 kg =55kg

Hope you understand...

7 0
1 year ago
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