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2 years ago

1. Is a Square a rectangle?(Always, Never, Sometimes. Are all the answers you can say for these)

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

5 0

Answer:

1. sometimes

2. always

3. always

4. always

Step-by-step explanation:

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You can draw a quadrilateral with two sets of parallel lines and no right angles. true false

yuradex [85]

False. When a quadrilateral has two sets of parallel sides ,like I drew below, all four corners form right angles.

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3 years ago

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How do I do it the one that is circled

butalik [34]

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2 years ago

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AACB = ADCE. If<br> AC = 5 and BC = 7<br> CD = [ ? ).<br> PLS HELP LOL PLS

FromTheMoon [43]

Answer:

CD = 5

Step-by-step explanation:

AC = 5

BC = 7

∆ACB ≅ ∆DCE, therefore,

AC = CD,

BC = CE, and,

AB = DE

Thus,

AC = CD = 5

CD = 5

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2 years ago

Diego wants to have $1,000,000 in 5 years. He plans to invest $250,000 to start and make yearly payments of $125,000 to the acco

julia-pushkina [17]

Answer:

Yes

Step-by-step explanation:

With the $875,000 from his input alone he is really close to $1,000,000 and doing simple intrest on the $250,000 is $105,000 a year is he earns 3.5% intrest a month.

So in 5 years he'll have about $1,662,500 using simple intrest but with compound it'd be more like 2mil

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1 year ago

How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

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3 years ago