Answer:
B)Diffraction
Explanation:
The concept of diffraction in the field of physics is defined as the deflection of a wave when it crosses an opening or hits the edge of an opaque element. Diffraction is a phenomenon that involves all waves: electromagnetic, radio, sound, etc., and it is possible to predict their behavior using different mathematical approaches. There is a method of analysis called the Huygens principle, which allows us to understand diffraction as a wavefront that is seen as a series of emitters capable of redirecting the wave when it oscillates and thus promotes propagation. Although the waves produced by the oscillators are spherical, their interference causes a flat wave that moves in the same direction as the initial one.
Answer:
A. 
B. P ≈ 0
Explanation:
In order to calculate the magnetic field strength we have to use the magnetic field strength of a straight wire.
(eq. I)
B = magnetic field strength at distance d
I = current (A)
mi = represented by the greek letter μ, represents the permeability of the free space, which is: 4 × π 10^(-7) T m/A
d = distance from the wire
By replacing the values in eq I, we have the following:
(eq II)
The earth magnetic field in the surface variates from 25 to 65 microteslas. Thus:
P = Percentage from the wires/percentage of the earth
∵ 
∴
P ≈ 0
Answer:
For mass m 1 newton 2nd law
F=m 1 a 1
5=m 1 ×10
m 1 = 2
1
kg
For mass m 2
F=m 2 a 2
5=m 2
×20
m 2
= 4
1 kg
if tied together
Total mass =m 1 +m 2 = 1/2 +1/4=3/4kg
Now
F=M
T Q
T
a T = 5/m T = 5×4/3 = 3
/20m/s^2
Explanation:
Answer:
Current flowing in the cell will be equal to 0.1284 mA
Explanation:
We have given charge q = 3.70 C
And time through which charge is flowing = 8 hour
We know that 1 hour = 60 minutes, and 1 minute = 60 sec
So 1 hour = 60×60 = 3600 sec
So 8 hour = 8×3600 = 28800 sec
We know that current is rate time rate of flow of charge
So current 
So current flowing in the cell will be equal to 0.1284 mA
Answer: 1960 N
Explanation:
The bear is sliding down at constant velocity: this means that its acceleration is zero, so the net force is also zero, according to Newton's second law:
There are two forces acting on the bear: its weight W, pulling downward, and the frictional force Ff, pulling upward. Therefore, the net force is given by the difference between the two forces:
From the previous equation, we find that the frictional force is equal to the weight of the bear:
