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3 years ago

A green plant has_____energy

1 answer:

4 0

A green plant has Chemical energy.

This chemical energy is stored as Chlorophyll which in turn reacts with sunlight and water, to form sugar through the process of Photosynthesis.

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The strength of the electric field 0.5 m from a 6 uC charge is

Triss [41]

Answer:

E= 2.158× 10*5N/C

Explanation:

K= 8.99×10*9, q= 6×10*-6C, d= 0.5m

E= kq/d*2

E= (8.99×10*9× 6×10*-6)/0.5*2

E= 215760

E= 2.158 ×10*5N/C

5 0

3 years ago

If you lift two loads up one story, how much work do you do compared to lifting just one load up one story?

Daniel [21]

Answer:a

Explanation:

We have to lift the load two loads up one story, so energy required is

let m be the mass of each load and h is the height of each story

Energy $E_1=2\times m\times g\times \h$

$E_1=2mgh$

Here energy gained is the potential energy which depends upon the datum(floor).

For lifting one load up one story

Energy required

$E_2=mgh$

thus $E_2$ is half of $E_1$

So option a is correct

6 0

3 years ago

Tell me pls<br>question: one way to protect property from damage. (hurricane) (hurricane)

postnew [5]

Answer:

hide on a place where there is no windows take a radio

Explanation:

5 0

3 years ago

Read 2 more answers

I need help with question ii) Calculate the speed of these radio waves.

Sergeeva-Olga [200]

Answer:

Speed = Wavelength x Wave Frequency. In this equation, wavelength is measured in meters and frequency is measured in hertz (Hz), or number of waves per second. Therefore, wave speed is given in meters per second, which is the SI unit for speed.

4 0

2 years ago

As shown in the diagram, two forces act on an object. The forces have magnitudes F1 = 5.7 N and F2 = 1.9 N. What third force wil

galina1969 [7]

Answer:

Second option 6.3 N at 162° counterclockwise from

F1->

Explanation:

Observe the attached image. We must calculate the sum of all the forces in the direction x and in the direction y and equal the sum of the forces to 0.

For the address x we have:

$-F_3sin(b) + F_1 = 0$

For the address and we have:

$-F_3cos(b) + F_2 = 0$

The forces $F_1$ and $F_2$ are known

$F_1 = 5.7\ N\\\\F_2 = 1.9\ N$

We have 2 unknowns ( $F_3$ and b) and we have 2 equations.

Now we clear $F_3$ from the second equation and introduce it into the first equation.

$F_3 = \frac{F_2}{cos (b)}$

Then

$-\frac{F_2}{cos (b)}sin(b)+F_1 = 0\\\\F_1 = \frac{F_2}{cos (b)}sin(b)\\\\F_1 = F_2tan(b)\\\\tan(b) = \frac{F_1}{F_2}\\\\tan(b) = \frac{5.7}{1.9}\\\\tan^{-1}(\frac{5.7}{1.9}) = b\\\\b= 72\°\\\\m = b +90\\\\\m= 162\°$

Then we find the value of $F_3$

$F_3 = \frac{F_1}{sin(b)}\\\\F_3 =\frac{5.7}{sin(72\°)}\\\\F_3 = 6.01 N$

Finally the answer is 6.3 N at 162° counterclockwise from

F1->

7 0

3 years ago