What is the distance traveled when a car goes 20 m/s for 60 seconds?

Physics

1 answer:

AfilCa [17]3 years ago

5 0

Answer:

1200 m

Explanation:

s= vt

s= 20m/s × 60 s

s= 1200 m

hope it hepls

for any question comment me ❤❤

You might be interested in

If density of water is 300kg m3 and hight 4m of water find the pressure of water ?<br>

iren [92.7K]

Answer:

11, 760 Pa.

Explanation:

By applying formula P= pgh, where P is pressure, p is density, g is gravitational acceleration (9.8 m\s2) and h is height of water level. Putting values in the formula, you can have the correct answer.

3 0

3 years ago

The visible surface of the Sun, which is also the deepest layer we can see with our eyes, is in which region of the Sun?

Nina [5.8K]

It is the photosphere

5 0

3 years ago

g Initially, the motorcycle travels along a straight road with a speed of 35 m/s (this is almost 80 mph). The maximum decelerati

astraxan [27]

Given:

Initial speed of the motorcycle (u) = 35 m/s

Final speed of the motorcycle (v) = 0 m/s (Complete Stop)

Maximum deceleration of the motorcycle (a) = -1.2 m/s²

Required Equation:

$\boxed{\bf{ v = u + at}}$

Answer:

By substituting values in the equation, we get:

$\rm \longrightarrow 0 = 35 + ( - 1.2)t \\ \\ \rm \longrightarrow 0 = 35 - 1.2t \\ \\ \rm \longrightarrow 35 - 1.2t = 0 \\ \\ \rm \longrightarrow 35- 35 - 1.2t = 0 - 35 \\ \\ \rm \longrightarrow - 1.2t = - 35 \\ \\ \rm \longrightarrow \dfrac{ - 1.2t}{ - 1.2} = \dfrac{ - 35}{ - 1.2} \\ \\ \rm \longrightarrow t = 29.167 \: s$