Answer:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Answer: 0.8022 | This is your answer
Step-by-step explanation:
Well this question is a bit baud but I will try to answer my best.
To find the difference of any number you just need to subtract.
So a-b=c | c is your difference.
So in this problem 1-0.1978 would equal 0.8022
Answer:
x=2
Step-by-step explanation:
-3*(x-2)-(2*x-3)-(5-(4*x-2))=0
((0 - 3 • (x - 2)) - (2x - 3)) - (7 - 4x) = 0
2 - x = 0
-x+2 = 0
Subtract 2 from both sides of the equation :
-x = -2
Multiply both sides of the equation by (-1) : x = 2
Answer:
<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
- First we need to convert it into y=mx+c form
- Now create table using this
<h3><u>Table</u><u>:</u><u>-</u></h3>
Hence the intercepts are
You have to do this because the answe is the 2nx
