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lesya692 [45]
3 years ago
5

Graph the following inequality 6x-2y>8 Please help me and show me how to graph it.

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

6x - 2y > 8

<u><em>First, solve the inequality (Isolate the y-variable & put it in function format):</em></u>

<u><em /></u>6x - 2y > 8\\-2y > 8 - 6x\\(-1)(-2y) > (-1)(8-6x)\\2y < 6x-8\\y < \frac{6x-8}{2} \\y < 3x - 4

<u><em>Second, graph the function y = 3x - 4 on the graph.</em></u>

  • It should be linear.
  • Because the inequality is < and not ≤, the values on the line aren't included in the solution, so your line should be dotted, not solid.

<u><em>Third, shade in the area below the line(where y-values are smaller).</em></u>

  • Since the inequality is <, that means the solutions are smaller than the solutions of the function 3x - 4.

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Calculate S58 for the arithmetic sequence {an}= {5/6n+1/3} If you could show me the steps that would be great. I keep following
Amanda [17]

Answer is 8671/6 which is the third choice

===================================

Work Shown:

Find the first term of the sequence by plugging in n = 1

a_n = (5/6)*n + 1/3

a_1 = (5/6)*1 + 1/3    replace n with 1

a_1 = 5/6 + 1/3

a_1 = 5/6 + 2/6

a_1 = 7/6

Repeat for n = 58 to get the 58th term

a_n = (5/6)*n + 1/3

a_58 = (5/6)*58 + 1/3    replace n with 58

a_58 = (5/6)*(58/1) + 1/3

a_58 = (5*58)/(6*1) + 1/3

a_58 = 290/6 + 1/3

a_58 = 145/3 + 1/3

a_58 = 146/3

Now we can use the s_n formula below with n = 58

s_n = (n/2)*(a_1 + a_n)

s_58 = (58/2)*(a_1 + a_58)    replace n with 58

s_58 = (58/2)*(7/6 + a_58)   replace a_1 with 7/6

s_58 = (58/2)*(7/6 + 146/3)   replace a_58 with 146/3

s_58 = (58/2)*(7/6 + 292/6)

s_58 = (58/2)*(299/6)

s_58 = (58*299)/(2*6)

s_58 = 17342/12

s_58 = 8671/6


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