Answer: 
<u>Simplify both sides of the equation</u>
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(Combine Like Terms)

<u>Subtract 1 from both sides</u>
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<u>Divide both sides by 2.2</u>
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It was 150, went down to 100, so it went 50 bucks.
now, if we take 150 as the 100%, what is 50 off of it in percentage?
Answer:
The upper limit of a 95% confidence interval for the population mean would equal 83.805.
Step-by-step explanation:
The standard deviation is the square root of the variance. Since the variance is 25, the sample's standard deviation is 5.
We have the sample standard deviation, not the population, so we use the t-distribution to solve this question.
T interval:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 15 - 1 = 14
Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 0.95(
). So we have T = 1.761
The margin of error is:
M = T*s = 1.761*5 = 8.805.
The upper end of the interval is the sample mean added to M. So it is 75 + 8.805 = 83.805.
The upper limit of a 95% confidence interval for the population mean would equal 83.805.
It's an expression that consists of variables and coefficients that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.
example:
x2 − 4x + 7