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ioda
2 years ago
15

Hi can someone please help me with this question

Mathematics
2 answers:
olga2289 [7]2 years ago
4 0

Answer: B. 3x + 1/5

tom's pencil is longer than Ellen's pencil:

5x + 2/5 - (2x + 1/5) = 5x - 2x + 2/5 - 1/5 = 3x + 1/5 (cm)

Step-by-step explanation:

arlik [135]2 years ago
4 0

Answer:

The answer i got for this question is 3x + 2/5

correct me if i'm wrong

Step-by-step explanation:

hope this helps

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A graph has minutes on the x-axis and ounces of popcorn on the y-axis. A curve goes through points (0, 0), (50, 12), and (110, 1
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No :)

Step-by-step explanation:

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earnstyle [38]

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1

Step-by-step explanation:

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Find all unit vectors that are orthogonal to the vector u = 1, 0, −4 .
KIM [24]

Answer:

Step-by-step explanation:

Given:

u = 1, 0, -4

In unit vector notation,

u = i + 0j - 4k

Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.

If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then

u. v = 0                    [<em>substitute for the values of u and v</em>]

=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k)  = 0               [<em>simplify</em>]

=> v₁ + 0 - 4v₃ = 0

=> v₁ = 4v₃

Plug in the value of v₁ = 4v₃ into vector v as follows

v = 4v₃ i + v₂ j + v₃ k              -------------(i)

Equation (i) is the generalized form of all vectors that will be orthogonal to vector u

Now,

Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

\frac{v}{|v|}

Where;

|v| = \sqrt{(4v_3)^2 + (v_2)^2 + (v_3)^2}

|v| = \sqrt{17(v_3)^2 + (v_2)^2}

\frac{v}{|v|} = \frac{4v_3i + v_2j + v_3k}{\sqrt{17(v_3)^2 + (v_2)^2}}

This is the general form of all unit vectors that are orthogonal to vector u

where v₂ and v₃ are non-zero arbitrary real numbers.

3 0
3 years ago
Plz answer im desperate thank you!
Law Incorporation [45]
The answer is 4 hope this helps
6 0
3 years ago
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Please help domain and range
Naddik [55]

Answer: #13: Domain = (-∞,∞) Range = (-∞,0]

#14: Domain = (-∞,∞), Range = (-∞,∞)

Step-by-step explanation: The domain is all possible x values for a graph and the range is all possible y values.

7 0
2 years ago
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