You use these formulas:
Q1 - 1.5(IQR)
Q3 + 1.5(IQR)
If any numbers fall outside the range of the solutions to the above equations, then they're an outlier.
Answer:
64%
Step-by-step explanation:
Given
Occupied = 608
UnOccupied = 342
The total number of room is the sum of these 2. So
Total Room = 608 + 342 = 950 rooms
To find percentage of rooms that were occupied, we have to divide the occupied number of rooms by the total number of rooms. Then we have to multiply that answer by 100 to get the "percentage". let's do this:

Then

So, 64% of the rooms were occupied.
Answer:
BE ≈ 92 m
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The square of the tangent is equal to the product of the external part of the secant and the entire secant, that is
BE² = 59(59 + 83) = 59 × 142 = 8378 ( take the square root of both sides )
BE =
≈ 92 m ( to the nearest metre )
Answer:
The solution is:
Part A.
which is sqrt(5)^7k/3[/tex]
Part B. k = 18/7
Step-by-step explanation:
Part A.
To solve this part, we're going two use THREE important properties of exponents:
1. 
2. 
3. ![\sqrt[n]{x^{m}} = x^{\frac{m}{n} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%20%3D%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D)
Let's work the numerator using the properties 1, 2 and 3:

Let's work the denominator using the properties 1, 2 and 3:

Now dividing the numerator by the denominator:

Part B
if 
Then:

So 
Solving for k, we have:
k = 18/7
Answer:
3/4 a pint
Step-by-step explanation:
1/4 + 2/4 = 3/4