II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
Simplifying
4x + 16 + -1x = 22 + 6
Reorder the terms:
16 + 4x + -1x = 22 + 6
Combine like terms: 4x + -1x = 3x
16 + 3x = 22 + 6
Combine like terms: 22 + 6 = 28
16 + 3x = 28
Solving
16 + 3x = 28
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-16' to each side of the equation.
16 + -16 + 3x = 28 + -16
Combine like terms: 16 + -16 = 0
0 + 3x = 28 + -16
3x = 28 + -16
Combine like terms: 28 + -16 = 12
3x = 12
Divide each side by '3'.
x = 4
Simplifying
x = 4
The answer is chinese medicine.
Circumference of a circle is C = 2πr.
part 1)
so the radius of the smaller gear is 3 inches, so after a full rotation, namely a revolution, the smaller gear has covered an arc of 2π(3), or 6π.
what angle has the larger gear of 7 inches in radius, has it covered with an arc of 6π?

part 2)
since the larger gear has a radius of 7, in a revolution it will have an arc of 2π(7), or 14π.
now, we know the smaller gear does a 6π arc in a revolution, how many revolutions will it do in an arc of 14π?
1.solve for y
2x+4y=12
<u> </u><span><u> -2x -2x</u>
</span><u>4y</u>=<u>12-2x</u>
<u>4 4</u>
y=3-1/2x
step2 plug in y and solve for x
2x+8y=24
2x+8(3-1/2x)= 24
2x+24-4x=24
<u>-2x</u>=<u>0
</u><u>-2 -2</u>
x=0
last step plug in x and solve for y
y=3-1/2x(0)
y=3