In the diagram below ABE = 65° and DĈF = 32º. E- B 650 D 32°C A F Calculate the size of EBC

19, 25, 31, 19, 34, 22, 31, 34 Mean: Median: Mode: Range:

77julia77 [94]

Answer:

all the numbers are gong by adding 6

4 0

3 years ago

Read 2 more answers

Which table represents exponential growth? A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. T

Papessa [141]

Answer:

Table 2

Step-by-step explanation:

We have the tables:

Table 1:

x: 1 2 3 4

y: 2 4 6 8

Table 2:

x: 1 2 3 4

y: 2 4 8 16

Table 3:

x: 1 2 3 4

y: 2 4 7 11

Table 4:

x: 1 2 3 4

y: 2 4 6 10

An exponential growth data set will show a common ratio between y values. Let's look at each of the ratios from each table.

Table 1:

8/6 = 4/3

6/4 = 3/2

Already, we can see that 4/3 ≠ 3/2, which means that this doesn't have a common ratio. So Table 1 is wrong.

Table 2:

16/8 = 2

8/4 = 2

4/2 = 2

The common ratio here is 2, so we know this is correct.

Table 3:

11/7 = 1.57

7/4 = 1.75

Again, we can see that 1/57 ≠ 1.75, so this is wrong.

Table 4:

10/6 = 1.67

6/4 = 1.5

Again, there is no common ratio here, so this is wrong.

The answer is thus Table 2.

8 0

3 years ago

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URGENT!! Really need help on this test

Katyanochek1 [597]

Answer:

G= L &M

H=L &M

K=P&N

J=P&N

7 0

3 years ago

Please prove this........

Crazy boy [7]

Answer: see proof below

Step-by-step explanation:

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

Proof LHS → RHS

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

3 years ago

A new car is purchased for 22400 dollars. The value of the car depreciates at 11% per year. To the nearest tenth of a year , how

m_a_m_a [10]

Answer:

t= 12.9 years

Step-by-step explanation:

Value after t years = initial value ( 1 - r )^t

Where,

Value after t years= $5000

Initial value = $22,400

r= depreciation rate = 11%

t= length of time (years)

Value after t years = initial value ( 1 - r )^t

5000 = 22,400 ( 1 - 0.11)^t

5000 = 22,400(0.89)^t

Divide both sides by 22,400

(0.89)^t = 5000 / 22,400

(0.89)^t = 0.2232

Take the log of both sides

t log 0.89 = log 0.2232

t= log 0.2232 / log 0.89

= -0.6513 / -0.0506

= 12.87

t= 12.9 years

5 0

3 years ago

In the diagram below ABE = 65° and DĈF = 32º. E- B 650 D 32°C A F Calculate the size of EBC​

In the diagram below ABE = 65° and DĈF = 32º. E- B 650 D 32°C A F Calculate the size of EBC