The correct answer is C my friend
The surface area of the balloon is 249 in².
<h3>What is the surface area of the balloon ?</h3>
A balloon has the shape of a sphere. The distance round the sphere is equal to the circumference of the sphere.
Circumference of the sphere = 2πr
Where:
- r = radius
- π = pi = 22 / 7
Radius - circumference / 2π
28 / ( 2 x 22/7) = 4.45 inches
Surface area of a sphere = 4πr²
4 x 22/7 x 4.45² = 249 in²
To learn more about the surface area of a sphere, please check: brainly.com/question/27267844
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1. You have that the circle that defines the part of the planter wall which gets watered by the sprinkler is: (x−10)²+(y+12)²<span>=36.
2. The standard form for the equation of a circle is:
(x-h)</span>²+(y-k)²=r²
(h,k) is the center point.
r is the radius.
3. Keeping this on mind, you can find the value of the radius, as below:
r²=36
r=√36
r=6 m
4. Then, the diameter of the circle is:
D=2r
D=2(6m)
D=12 m
<span>
What is the diameter, in meters, of the circular area that gets watered by the sprinkler?</span>
The answer is: 12 m
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1
Starting with the left: Note that cos²θ + </span><span>sin²θ = 1.
In the same way: </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore cos²3θ = 1 - <span>sin²3θ
</span> From the top: (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ
= 2/<span>sin² 3θ - 1; But 1/</span><span>sinθ = csc</span><span>θ, Similarly </span>1/sin3θ = csc3θ
= 2 *(1/sin<span>3θ)² - 1</span>
= 2csc²3θ - 1. Therefore LHS = RHS. QED.
Answer: I’m not sure just trying to get Brainly points to ask more questions. Sorry :/
Step-by-step explanation: