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2 years ago

Jada’s babysitter is four times Jada’s current age. In 5 years, Jada will be half her babysitter’s current age.

Mathematics

1 answer:

lora16 [44]2 years ago

7 0

Answer:

Step-by-step explanation:

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Please explain I don’t I understand help

djyliett [7]

Answer:

Step-by-step explanation:

f (x) = (5(-4)) + a) (3/5 + 4) ( 6 + b)

f (x) = (-20 + a) (6 2/5) (6 + b)

f ( -20 ) = -20 + -20 (a) (6 2/5) (6 + b)

f ( -20 - 6 2/5 ) = (a) (6 2/5 -6 2/5) (6 + b)

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2 years ago

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

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1 year ago

Answer these for a brainliest

natita [175]

5.
x - y = 11
2x + y = 19
2x - 2y = 22
2x + y = 19
-3y = 3
y = -1
x + 1 = 11
x = 10
(10, -1)

6.
-6x + 6y = 6
-6x + 3y = -12
3y = 18
y = 6
-6x + 36 = 6
-6x = -30
x = 5
(5, 6)

4 0

2 years ago