Jada’s babysitter is four times Jada’s current age. In 5 years, Jada will be half her babysitter’s current age.

Gabrielle is traveling to Mexico and needs to exchange $440 into Mexican pesos. If each dollar is worth 11.84 pesos, how many pe

alexira [117]

Answer:

5209.60 pesos

Step-by-step explanation:

$440 x 11.84= 5209.60

6 0

3 years ago

Equivalent to 13/5 A.2.4 B.2.45 C.2.55 D.2.6 NEED HELP ASAP!!!!

jek_recluse [69]

D is the answer because 13 goes into 5 twice and 3 Is left over multiply that by two to get 6/10 than that it's equivalent to .6 so it is 2.6

7 0

3 years ago

How do you multiply decimals?

Ulleksa [173]

I found this online, hope it helps

Just follow these steps:
Multiply normally, ignoring the decimal points.
Then put the decimal point in the answer - it will have as many decimal places as the two original numbers combined.

5 0

3 years ago

Find the absolute maximum and absolute minimum values of the function f(x, y) = x 2 + y 2 − x 2 y + 7 on the set d = {(x, y) : |

dsp73

Looks like $f(x,y)=x^2+y^2-x^2y+7$ .

$f_x=2x-2xy=0\implies2x(1-y)=0\implies x=0\text{ or }y=1$

$f_y=2y-x^2=0\implies2y=x^2$

If $x=0$ , then $y=0$ - critical point at (0, 0).
If $y=1$ , then $x=\pm\sqrt2$ - two critical points at $(-\sqrt2,1)$ and $(\sqrt2,1)$

The latter two critical points occur outside of $D$ since $|\pm\sqrt2|>1$ so we ignore those points.

The Hessian matrix for this function is

$H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2-2y&-2x\\-2x&2\end{bmatrix}$

The value of its determinant at (0, 0) is $\det H(0,0)=4>0$ , which means a minimum occurs at the point, and we have $f(0,0)=7$ .

Now consider each boundary:

If $x=1$ , then

$f(1,y)=8-y+y^2=\left(y-\dfrac12\right)^2+\dfrac{31}4$

which has 3 extreme values over the interval $-1\le y\le1$ of 31/4 = 7.75 at the point (1, 1/2); 8 at (1, 1); and 10 at (1, -1).

If $x=-1$ , then

$f(-1,y)=8-y+y^2$

and we get the same extrema as in the previous case: 8 at (-1, 1), and 10 at (-1, -1).

If $y=1$ , then

$f(x,1)=8$

which doesn't tell us about anything we don't already know (namely that 8 is an extreme value).

If $y=-1$ , then

$f(x,-1)=2x^2+8$

which has 3 extreme values, but the previous cases already include them.

Hence $f(x,y)$ has absolute maxima of 10 at the points (1, -1) and (-1, -1) and an absolute minimum of 0 at (0, 0).

3 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Natalija [7]

Answer: C & D

Step-by-step explanation:

A binomial experiment must satisfy ALL four of the following:

A fixed number of trials
Each trial is independent of the others
There are only two outcomes (Success & Fail)
The probability of each outcome remains constant from trial to trial.

A) When the spinner is spun three times, X is the sum of the numbers the spinner lands on.

→ #3 is not satisfied (#4 is also not satisfied)

B) When the spinner is spun multiple times ...

→ #1 is not satisfied

C) When the spinner is spun four times, X is the number of times the spinner does not land on an odd number.

→ Satisfies ALL FOUR

A fixed number of trials = 4
Each trial is independent of the others = each spin is separate
There are only two outcomes = Not Odd & Odd
The probability of each outcome remains constant from trial to trial = P(X = not odd) = 0.50 for each spin

D) When the spinner is spun five times, X is the number of times the spinner lands on 1.

→ Satisfies ALL FOUR

A fixed number of trials = 5
Each trial is independent of the others = each spin is separate
There are only two outcomes = 1 & Not 1
The probability of each outcome remains constant from trial to trial = P(X = 1) = 0.17 for each spin

3 0

3 years ago